怎么替换字符串中的空格君？

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怎么把字符串的里的空格君都给替换了呢？我之前没用C语言写过，今天尝试了下，小编太笨了，写写改改，到这会儿终于弄好了。

先谈谈思路，既然要将空格替换，我就要现将空格标示出来，此处借助的是字符数组的下标i来实现。用一个中间字符串变量tmp来表示替换的结果，给tmp分配适当的空间。当一开始有空格的时候就要先将要替换的字符串接入，有几个空格就重复strcat几次一直到开始的空格全部被替换，然后将原字符串从首个非空格处接入tmp。i向后移动直到下一个空格处（标示tmp的下标要同步往后移动）再次执行上一步操作直到循环不满足条件。

<span style="font-size: 24px; font-family: Arial, Helvetica, sans-serif;">//替换字符串中的所有空格为％20</span>

<span style="font-size: 24px;">#include<stdio.h>#include<string.h>#include<malloc.h>void replace(char *str,char *ss)//str原字符串，ss是要替换的字符串{        int i = 0;int j = -1;   //j下标从-1开始，因为数组从0 开始计数int n1 = strlen(str);int n2 = strlen(ss);char *tmp = (char*)malloc(sizeof(char) * n1 * 2);        // 为tmp分配合适的空间while(i < n1 && str[i] == ' ')//循环替换开头的所有空格{tmp = strcat(tmp,ss);i++;j+=n2;}tmp = strcat(tmp,&(str[i]));//从首个非空字符接入       while(i < n1 ){if(str[i] == ' '){   tmp[j+1] = '\0';//在空格处接入ss           while(i < n1 && str[i] == ' ')                   {       tmp = strcat(tmp,ss);       i++;       j+= n2;           }tmp = strcat(tmp,&(str[i]));}               else{i ++;j ++;}}printf("%s\n",tmp);}int main(){char *str = "     hello sandy nice to meet to you";char *ss ="%20";printf("替换之前str = %s\n",str);printf("替换之后str = ");        replace(str,ss);return 0;}</span>

运行结果：

替换之前str = hello sandy nice to meet to you
替换之后str = %20%20%20%20%20hello%20sandy%20nice%20to%20meet%20to%20you

程序写的有些复杂，先记下，以后水平提高的时候再重整，(*^__^*) 嘻嘻……

<span style="font-size: 24px; font-family: Arial, Helvetica, sans-serif;">//替换字符串中的所有空格为％20</span>

<span style="font-size: 24px;">#include<stdio.h>#include<string.h>#include<malloc.h>void replace(char *str,char *ss){    int i = 0;int j = -1;int n1 = strlen(str);int n2 = strlen(ss);char *tmp = (char*)malloc(sizeof(char) * n1 * 2);while(i < n1 && str[i] == ' '){tmp = strcat(tmp,ss);i++;j+=n2;}tmp = strcat(tmp,&(str[i]));while(i < n1 ){if(str[i] == ' '){   tmp[j+1] = '\0';       while(i < n1 && str[i] == ' ')           {       tmp = strcat(tmp,ss);       i++;       j+= n2;       }tmp = strcat(tmp,&(str[i]));}        else{i ++;j ++;}}printf("%s\n",tmp);}int main(){char *str = "     hello sandy nice to meet to you";char *ss ="%20";printf("替换之前str = %s\n",str);printf("替换之后str = ");    replace(str,ss);return 0;}</span>

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