几秒后才能点按扭的源代码

来源:互联网 发布:手机淘宝开店认证几天 编辑:程序博客网 时间:2024/06/05 14:38
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几秒后才能点按扭的源代码
重点在于setTimeout方法的应用,IE6及FF2下测试通过

<input id="button" name="" type="button" value="10注册" disabled />
<script type="text/javascript">
window.onload
=function(){
    bindButton(
10);
}

function bindButton(num){
    window.setTimeout(
"viewButton("+num+")",1000);
}

function viewButton(i){
    
var obj=document.getElementById("button");
    i
=i-1;
    obj.value
=i+"注册";
    
if(i>0){
        bindButton(i);
    }
else{
        obj.value
="注册";
        obj.disabled
=false;
    }

}

</script>

摘自【http://bbs.blueidea.com/thread-2854393-1-1.html】

<script type="text/javascript" src="http://www.google.com/reader/ui/publisher.js"></script> <script type="text/javascript" src="http://www.google.com/reader/public/javascript/user/00697638153916680411/state/com.google/broadcast?n=5&callback=GRC_p(%7Bc%3A%22green%22%2Ct%3A%22%5Cu8FD9%5Cu4E9B%5Cu6587%5Cu7AE0%5Cu4E5F%5Cu503C%5Cu5F97%5Cu4E00%5Cu770B%22%2Cs%3A%22false%22%7D)%3Bnew%20GRC"></script>

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