等待block完成再执行下一句代码

来源：互联网发布：网络算命大师编辑：程序博客网时间：2024/04/29 02:25

我使用afnetworking发送一个post请求, 需要得到请求结果再执行下一步代码,现在我用过如下两种方式, 但都会造成程序卡住无法往下进行.但是我在另一个put请求用了相同的方法却可行, 哪位大神有了解过这种问题的?求解释

第一种: dispatch_semaphore_t

AFHTTPRequestOperationManager *manager = [AFHTTPRequestOperationManager manager];manager.requestSerializer = [AFJSONRequestSerializer serializer];__block dispatch_semaphore_t sem = dispatch_semaphore_create(0);[manager POST:@"http://172.16.100.85:8080/service/user/register" parameters:nil success:^(AFHTTPRequestOperation *operation, id responseObject) {    self.requestResult = ProtocolErrorSuccess;    if ([responseObject isKindOfClass:[NSDictionary class]]) {        self.responseData = responseObject;    }    dispatch_semaphore_signal(sem);} failure:^(AFHTTPRequestOperation *operation, NSError *error) {    self.requestResult = ProtocolErrorFailure;    dispatch_semaphore_signal(sem);}];dispatch_semaphore_wait(sem, DISPATCH_TIME_FOREVER);if(self.requestResult == ProtocolErrorSuccess) {    [self saveToken:self.responseData];}

第二种: NSCondition

[manager POST:@"http://172.16.100.85:8080/service/user/register" parameters:nil success:^(AFHTTPRequestOperation *operation, id responseObject) {    self.requestResult = ProtocolErrorSuccess;    if ([responseObject isKindOfClass:[NSDictionary class]]) {        self.responseData = responseObject;    }    [condition lock];    [condition signal];    [condition unlock];} failure:^(AFHTTPRequestOperation *operation, NSError *error) {    self.requestResult = ProtocolErrorFailure;    [condition lock];    [condition signal];    [condition unlock];}];[condition lock];[condition wait];[condition unlock];if(self.requestResult == ProtocolErrorSuccess) {    [self saveToken:self.responseData];}

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