[LeetCode] 3. Longest Substring Without Repeating Characters
来源：互联网 发布：linux 启动openoffice 编辑：程序博客网 时间：2024/05/21 23:00
思路:
开辟一个大小为256 * 4的数组作为哈希表存放每个字符最新的下标. 用一个start变量控制最新的开始处, 每次递归都会尝试更新结果. 时间复杂度O(n), 空间复杂度O(1).
int lengthOfLongestSubstring(string s) { if (s == "") return 0; int hash[256]; memset(hash, -1, 256 * sizeof(int)); int start = -1, res = 0; for (int i = 0; i < s.length(); i++) { // 如果之前的字符串内出现过当前字符, 则把start放到 // 之前出现的当前字符位置, 成为新的开始 if (hash[s[i]] > start) start = hash[s[i]]; res = max(res, i - start); hash[s[i]] = i; } return res;} 0 0
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