Android在多个Activity间传递对象及对象数组

假设对象为People类，包含信息姓名和年龄：

public class People{    public String strName;    public int iAge;    public People(String strName,int iAge){        this.strName = strName;        this.iAge = iAge;    }    public String getName(){        return strName;    }    public int getAge(){        return iAge;    }}

方法一：Serializable

必须条件：类实现了Serializable接口

public class People implements Serializable{    private static final long serialVersionUID = 1L;    public String strName;    public int iAge;    public People(String strName,int iAge){        this.strName = strName;        this.iAge = iAge;    }    public String getName(){        return strName;    }    public int getAge(){        return iAge;    }}

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传递对象
传递端：

People people = new People("John", 21);Intent intent = new Intent(SendActivity.this,RcvActivity.class);Bundle bundle = new Bundle();bundle.putSerializable("people", people);intent.putExtras(bundle);startActivity(intent);

接收端：

String strData = people.getName() + " " + people.getAge();Toast.makeText(getApplication(),strData, Toast.LENGTH_SHORT).show();

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传递对象数组：
传递端：

List<people> people = new ArrayList<people>();people.add(new People("John", 21));people.add(new People("Amy", 20));Bundle bundle = new Bundle();bundle.putSerializable("people", (Serializable) people);Intent intent = new Intent(SendActivity.this, RcvActivity.class);intent.putExtras(bundle);startActivity(intent);

接收端：

List<people> resultList = (List<people>) this.getIntent().getSerializableExtra("people");String strData = "";for (People p : resultList) {    strData = strData + p.strName + " " + p.iAge + "\n";}Toast.makeText(getApplication(), strData, Toast.LENGTH_SHORT).show();

还有Parcelabel方式来传递数据，懒了不想写了…