LeetCode之链表数相加

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问题描述:

/** * You are given two linked lists representing two non-negative numbers.  *  * The digits are stored in reverse order and each of their nodes contain a single digit. *  * Input: (2 -> 4 -> 3) + (5 -> 6 -> 4) *  * Output: 7 -> 0 -> 8 */

就是说有两个链表代表两个非负的整数,每一个链表节点都存储一个单个的数字,并且节点存储的顺序和整数的数字排列顺序是相反的,如上所示,数a为342,数b为465,相加为807.
解题思想还是从数的末尾开始相加,对于这道题来说也就是从两个链表的开头进行运算,期间要声明一个变量来作为进位。
这道题和我前面一篇博客是类似的,在进行运算时要对两个数“对齐”,即在对齐的情况下是一种运算,不对齐又是另一种情况。下面是代码:

public class AddTwoNumbers {    public static ListNode addTwoNumbers(ListNode l1, ListNode l2) {        if (l1 == null)            return l2;        if (l2 == null)            return l1;        ListNode head = new ListNode(0);        ListNode cur = head;        int plus = 0;        while (l1 != null && l2 != null) {            int sum = l1.val + l2.val + plus;            plus = sum / 10;            sum = sum % 10;            cur.next = new ListNode(sum);            cur = cur.next;            l1 = l1.next;            l2 = l2.next;        }        if (l1 != null) {            if (plus != 0) {                cur.next = addTwoNumbers(l1, new ListNode(plus));            } else {                cur.next = l1;            }        } else if (l2 != null) {            if (plus != 0) {                cur.next = addTwoNumbers(l2, new ListNode(plus));            } else {                cur.next = l2;            }        } else if (plus != 0) {            cur.next = new ListNode(plus);        }        return head.next;    }    public static void main(String args[])    {        ListNode l1=new ListNode(2);        l1.next=new ListNode(4);        l1.next.next=new ListNode(3);        ListNode r1=new ListNode(5);        r1.next=new ListNode(6);        r1.next.next=new ListNode(4);        ListNode newnode=addTwoNumbers(l1,r1);        while(newnode!=null)        {            System.out.println(newnode.val);            newnode=newnode.next;        }    }}

在声明Listnode时,竟然感觉有点吃力,忘了数据结构是怎么样的了,然后查了一下才解决,其实,用java声明单链表是很简单的,如下所示:

public class ListNode {    int val;    ListNode next;    public ListNode(int x){        val = x;        next = null;    }}
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