Gym 100735 - I. Yet another A + B

题目链接:

http://codeforces.com/gym/100735/problem/I；

题意:

给出三个数A,B,C，如果三个数随机排列满足 两个相加等于第三个 的情况输出YES， 否则NO

题解:

大数加法

AC代码 （来自hacb教练）

#include <iostream>#include <algorithm>#include <string>#include <cstring>#include <stdio.h>using namespace std;struct Tr{    int num[120];    Tr operator+(Tr a)const    {        Tr tm;        memset(tm.num, 0, sizeof(tm.num));        int in = 0, i;        for (i = 0;i < 120;i++)        {            tm.num[i] = (num[i]+a.num[i]+in)%10;            in = (num[i]+a.num[i]+in)/10;        }        return tm;    }    bool operator==(Tr a)const    {        int i;        for (i = 119;i >= 0;i--)        {            if (num[i] != a.num[i]) return false;        }        return true;    }}A, B, C;char a[110], b[110], c[110];int main() {    int i, j;    while (~scanf("%s%s%s", a, b, c)) {        memset(A.num, 0, sizeof(A.num));        memset(B.num, 0, sizeof(B.num));        memset(C.num, 0, sizeof(C.num));        int la = strlen(a), lb = strlen(b), lc = strlen(c);        for (i = la-1;i >= 0;i--) A.num[la-1-i] = a[i]-'0';        for (i = lb-1;i >= 0;i--) B.num[lb-1-i] = b[i]-'0';        for (i = lc-1;i >= 0;i--) C.num[lc-1-i] = c[i]-'0';        if (A+B == C || A+C == B || B+C==A) puts("YES");        else if (A+A == C || B+B==C || B+B==A || C+C == B || C+C == A || A+A==B) puts("YES");        else puts("NO");    }}