(LeetCode)Power of Four --- 4的次方，python实现
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Given an integer (signed 32 bits), write a function to check whether it is a power of 4.
Example:
Given num = 16, return true. Given num = 5, return false.
Follow up: Could you solve it without loops/recursion?
Credits:
Special thanks to @yukuairoy for adding this problem and creating all test cases.
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解题分析：
对于这种的题目，类似于求解3, 2的次方一样。可以无限循环除以4然后判断最后能否除尽。
class Solution(object): def isPowerOfFour(self, num): while num and (num%4==0): num /= 4 return num == 1
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