hdoj5053the Sum of Cube(数学,打表)
来源:互联网 发布:中国真实gdp数据 编辑:程序博客网 时间:2024/05/17 06:12
Description
A range is given, the begin and the end are both integers. You should sum the cube of all the integers in the range.
Input
The first line of the input is T(1 <= T <= 1000), which stands for the number of test cases you need to solve.
Each case of input is a pair of integer A,B(0 < A <= B <= 10000),representing the range[A,B].
Output
For each test case, print a line “Case #t: ”(without quotes, t means the index of the test case) at the beginning. Then output the answer – sum the cube of all the integers in the range.
Sample Input
2
1 3
2 5
Sample Output
Case #1: 36
A range is given, the begin and the end are both integers. You should sum the cube of all the integers in the range.
Input
The first line of the input is T(1 <= T <= 1000), which stands for the number of test cases you need to solve.
Each case of input is a pair of integer A,B(0 < A <= B <= 10000),representing the range[A,B].
Output
For each test case, print a line “Case #t: ”(without quotes, t means the index of the test case) at the beginning. Then output the answer – sum the cube of all the integers in the range.
Sample Input
2
1 3
2 5
Sample Output
Case #1: 36
Case #2: 224
代码:
#include<stdio.h>int main(){__int64 a[10000+11];__int64 i;for( i=1;i<=10000;i++){a[i]=i*i*i;}int t;scanf("%d",&t);int k=1;while(t--){__int64 n,m;__int64 ans=0;scanf("%I64d %I64d",&n,&m);for(i=n;i<=m;i++){ans+=a[i];}printf("Case #%d: %I64d\n",k++,ans);}return 0;}思路:注意__int64 还有数组大小。
0 0
- hdoj5053the Sum of Cube(数学,打表)
- hdoj5053the Sum of Cube
- hdoj5053the Sum of Cube
- HDU-5053-the Sum of Cube【打表】
- hdoj the Sum of Cube 5053 (简单数学)
- HDU 5053 the Sum of Cube(数学求立方和)
- hdoj 5053 the Sum of Cube [数学 立方求和]
- the Sum of Cube
- The Sum of Cube
- the Sum of Cube
- the Sum of Cube
- the Sum of Cube
- POJ 2739 Sum of Consecutive Prime Numbers(数学,素数打表)
- poj2739 Sum of Consecutive Prime Numbers (素数打表)
- LOJ 1189 - Sum of Factorials(打表)
- HDU5053the Sum of Cube(水题)
- the Sum of Cube<hdoj5053>
- I - the Sum of Cube
- VS2013 Progress Control控件实现进度条
- MFC+opencv打开文件夹选择单张或多张图片
- 运行fast-rcnn-windows遇到的问题
- Linux/Unix select函数 及select/poll与epoll的对比
- C语言堆栈入门——堆和栈的区别
- hdoj5053the Sum of Cube(数学,打表)
- windows安装composer及使用教程
- 基于金字塔Lucas-Kanande寻找的视频流运动检测
- 双线性插值(Bilinear Interpolation)
- 部署好静态网页,上传文件在gh-pages分支转不到master的解决办法
- dom4j解析xml文档
- 4.文字在div垂直居中的方式
- VB查询数据库用于Ext.NET的Store
- TCP选项之SO_RCVBUF和SO_SNDBUF