tjut 5399

来源:互联网 发布:企业重要数据要及时 编辑:程序博客网 时间:2024/04/30 03:46
#pragma comment(linker, "/STACK:1024000000,1024000000")   #include<set>  #include<map>  #include<queue>  #include<stack>  #include<cmath>  #include<cstdio>  #include<vector>  #include<string>  #include<cstring>  #include<algorithm>  #include<functional>  using namespace std;  typedef long long LL;  const LL base = 1e9 + 7;  const int maxn = 105;  LL T, n, m, f[maxn], a[maxn][maxn];    inline void read(int &x)  {      char ch;      while ((ch = getchar())<'0' || ch>'9');      x = ch - '0';      while ((ch = getchar()) >= '0' && ch <= '9') x = x * 10 + ch - '0';  }    int main()  {      //read(T);      for (int i = f[0] = 1; i <= 100; i++) f[i] = f[i - 1] * i % base;      while (scanf("%I64d%I64d", &n, &m) != EOF)      {          LL tot = 0, ans = 1;          for (int i = 1; i <= m; i++)          {              scanf("%I64d", &a[i][1]);              if (a[i][1] == -1) tot++;              else for (int j = 2; j <= n; j++)              {                  scanf("%I64d", &a[i][j]);                  for (int k = j - 1; k; k--) if (a[i][j] == a[i][k]) ans = 0;              }          }          for (int i = 1; i < tot; i++) ans = ans * f[n] % base;          if (tot == 0)          {              for (int i = 1; i <= n; i++) a[0][i] = i;              for (int i = m; i; i--)                  for (int j = 1; j <= n; j++) a[0][j] = a[i][a[0][j]];              for (int i = 1; i <= n; i++) if (a[0][i] != i) ans = 0;          }          printf("%I64d\n", ans);      }      return 0;  }  


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