CodeForces 599B Spongebob and Joke

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K - Spongebob and Joke
Time Limit:2000MS     Memory Limit:262144KB     64bit IO Format:%I64d & %I64u
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Description

While Patrick was gone shopping, Spongebob decided to play a little trick on his friend. The naughty Sponge browsed through Patrick's personal stuff and found a sequence a1, a2, ..., am of length m, consisting of integers from 1 to n, not necessarily distinct. Then he picked some sequence f1, f2, ..., fn of length n and for each number ai got number bi = fai. To finish the prank he erased the initial sequence ai.

It's hard to express how sad Patrick was when he returned home from shopping! We will just say that Spongebob immediately got really sorry about what he has done and he is now trying to restore the original sequence. Help him do this or determine that this is impossible.

Input

The first line of the input contains two integers n and m (1 ≤ n, m ≤ 100 000) — the lengths of sequences fi and bi respectively.

The second line contains n integers, determining sequence f1, f2, ..., fn (1 ≤ fi ≤ n).

The last line contains m integers, determining sequence b1, b2, ..., bm(1 ≤ bi ≤ n).

Output

Print "Possible" if there is exactly one sequence ai, such that bi = fai for all i from 1 to m. Then print m integers a1, a2, ..., am.

If there are multiple suitable sequences ai, print "Ambiguity".

If Spongebob has made a mistake in his calculations and no suitable sequence ai exists, print "Impossible".

Sample Input

Input
3 33 2 11 2 3
Output
Possible3 2 1 
Input
3 31 1 11 1 1
Output
Ambiguity
Input
3 31 2 13 3 3
Output
Impossible

Hint

In the first sample 3 is replaced by 1 and vice versa, while 2 never changes. The answer exists and is unique.

In the second sample all numbers are replaced by 1, so it is impossible to unambiguously restore the original sequence.

In the third sample fi ≠ 3 for all i, so no sequence ai transforms into such bi and we can say for sure that Spongebob has made a mistake.

题意:给定长度n的序列f,长度为m的序列b,f[a[i]]=b[i],求长度为m,的序列a[i],多解输出Ambiguity,无解输出Impossible,有解输出Possible和序列

思路:对于这道题的题意,有点晕,思路看代码注释。

#include<stdio.h>#include<string.h>#include<algorithm>using namespace std;int n,m,i,j,k,l,f[110000],b[110000],a[110000],c[110000];int main(){while(scanf("%d%d",&n,&m)!=EOF){memset(f,0,sizeof(f));memset(b,0,sizeof(b));memset(a,0,sizeof(a));for(i=1;i<=n;i++){scanf("%d",&f[i]);if(c[f[i]])//判断是否是多次出现 c[f[i]]=-1;else c[f[i]]=i;}int flag=0;int ans=0;for(i=1;i<=m;i++){scanf("%d",&b[i]);if(c[b[i]]==0)//b[i]对应的f[a[i]]没有出现过 flag=1;else if(c[b[i]]==-1)//b[i]对应的f[a[i]]多次出现 ans=1;a[i]=c[b[i]];//求得a[i]; }if(flag==1)printf("Impossible\n");else if(ans==1)printf("Ambiguity\n");else{printf("Possible\n");for(i=1;i<m;i++)printf("%d ",a[i]);printf("%d\n",a[i]);}}return 0;}



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