Java 8十个lambda表达式案例

1. 实现Runnable线程案例

使用() -> {} 替代匿名类：

//Before Java 8:new Thread(new Runnable() {    @Override    public void run() {        System.out.println("Before Java8 ");    }}).start();//Java 8 way:new Thread( () -> System.out.println("In Java8!") ).start();     Output:too much code, for too little to doLambda expression rocks !!

你可以使用 下面语法实现Lambda:

(params) -> expression
(params) -> statement
(params) -> { statements }

如果你的方法并不改变任何方法参数，比如只是输出，那么可以简写如下：

() -> System.out.println("Hello Lambda Expressions");

如果你的方法接受两个方法参数，如下：

(int even, int odd) -> even + odd

2.实现事件处理

如果你曾经做过Swing 编程，你将永远不会忘记编写事件侦听器代码。使用lambda表达式如下所示写出更好的事件侦听器的代码。

// Before Java 8:JButton show =  new JButton("Show");show.addActionListener(new ActionListener() {     @Override     public void actionPerformed(ActionEvent e) {           System.out.println("without lambda expression is boring");        }     });// Java 8 way:show.addActionListener((e) -> {    System.out.println("Action !! Lambda expressions Rocks");});

在java 8中你可以使用Lambda表达式替代丑陋的匿名类。

 

3.使用Lambda表达式遍历List集合

//Prior Java 8 :List features = Arrays.asList("Lambdas", "Default Method", "Stream API", "Date and Time API");for (String feature : features) {   System.out.println(feature);}//In Java 8:List features = Arrays.asList("Lambdas", "Default Method", "Stream API", "Date and Time API");features.forEach(n -> System.out.println(n));// Even better use Method reference feature of Java 8// method reference is denoted by :: (double colon) operator// looks similar to score resolution operator of C++features.forEach(System.out::println);Output:LambdasDefault MethodStream APIDate and Time API

方法引用是使用两个冒号::这个操作符号。

4.使用Lambda表达式和函数接口

为了支持函数编程，Java 8加入了一个新的包java.util.function，其中有一个接口java.util.function.Predicate是支持Lambda函数编程：

public static void main(String[] args) throws Exception {List<String> languages = Arrays.asList("Java", "Scala", "C++", "Haskell", "Lisp");System.out.println("Languages which starts with J :");filter(languages, (str) -> ((String) str).startsWith("J"));System.out.println("Languages which ends with a ");filter(languages, (str) -> ((String) str).endsWith("a"));System.out.println("Print all languages :");filter(languages, (str) -> true);System.out.println("Print no language : ");filter(languages, (str) -> false);System.out.println("Print language whose length greater than 4:");filter(languages, (str) -> ((String) str).length() > 4);}public static void filter1(List<String> names, Predicate<String> condition) {for (String name : names) {if (condition.test(name)) {System.out.println(name + " ");}}}public static void filter(List<String> names, Predicate<String> condition){names.stream().filter((name)->(condition.test(name))).forEach((name)->{System.out.println(name + " ");});}

你能看到来自Stream API 的filter方法能够接受 Predicate参数, 能够允许测试多个条件。

5.复杂的结合Predicate 使用

java.util.function.Predicate提供and(), or() 和 xor()可以进行逻辑操作，比如为了得到一串字符串中以"J"开头的4个长度：

// We can even combine Predicate using and(), or() And xor() logical functions // for example to find names, which starts with J and four letters long, you // can pass combination of two Predicate Predicate<String> startsWithJ = (n) -> n.startsWith("J"); Predicate<String> fourLetterLong = (n) -> n.length() == 4;    names.stream()      .filter(startsWithJ.and(fourLetterLong))      .forEach((n) -> System.out.print("\nName, which starts with            'J' and four letter long is : " + n));

其中startsWithJ.and(fourLetterLong)是使用了AND逻辑操作。

 

6.使用Lambda实现Map 和 Reduce

最流行的函数编程概念是map，它允许你改变你的对象，在这个案例中，我们将costBeforeTeax集合中每个元素改变了增加一定的数值，我们将Lambda表达式 x -> x*x传送map()方法，这将应用到stream中所有元素。然后我们使用 forEach() 打印出这个集合的元素.

// applying 12% VAT on each purchase// Without lambda expressions:List costBeforeTax = Arrays.asList(100, 200, 300, 400, 500);for (Integer cost : costBeforeTax) {      double price = cost + .12*cost;      System.out.println(price);}// With Lambda expression:List costBeforeTax = Arrays.asList(100, 200, 300, 400, 500);costBeforeTax.stream().map((cost) -> cost + .12*cost)                      .forEach(System.out::println);Output112.0224.0336.0448.0560.0112.0224.0336.0448.0560.0

reduce() 是将集合中所有值结合进一个，Reduce类似SQL语句中的sum(), avg() 或count(), 

// Applying 12% VAT on each purchase// Old way:List costBeforeTax = Arrays.asList(100, 200, 300, 400, 500);double total = 0;for (Integer cost : costBeforeTax) { double price = cost + .12*cost; total = total + price; }System.out.println("Total : " + total);// New way:List costBeforeTax = Arrays.asList(100, 200, 300, 400, 500);double bill = costBeforeTax.stream().map((cost) -> cost + .12*cost)                                    .reduce((sum, cost) -> sum + cost)                                    .get();System.out.println("Total : " + bill);OutputTotal : 1680.0Total : 1680.0

 

7.通过filtering 创建一个字符串String的集合

Filtering是对大型Collection操作的一个通用操作，Stream提供filter()方法，接受一个Predicate对象，意味着你能传送lambda表达式作为一个过滤逻辑进入这个方法：

// Create a List with String more than 2 charactersList<String> filtered = strList.stream().filter(x -> x.length()> 2)                                        .collect(Collectors.toList());System.out.printf("Original List : %s, filtered list : %s %n",                   strList, filtered);Output :Original List : [abc, , bcd, , defg, jk], filtered list : [abc, bcd, defg]

 

8.对集合中每个元素应用函数

我们经常需要对集合中元素运用一定的功能，如表中的每个元素乘以或除以一个值等等.

// Convert String to Uppercase and join them using comaList<String> G7 = Arrays.asList("USA", "Japan", "France", "Germany",                                 "Italy", "U.K.","Canada");String G7Countries = G7.stream().map(x -> x.toUpperCase())                                .collect(Collectors.joining(", "));System.out.println(G7Countries);Output : USA, JAPAN, FRANCE, GERMANY, ITALY, U.K., CANADA

上面是将字符串转换为大写，然后使用逗号串起来。

 

9.通过复制不同的值创建一个子列表

使用Stream的distinct()方法过滤集合中重复元素。

// Create List of square of all distinct numbersList<Integer> numbers = Arrays.asList(9, 10, 3, 4, 7, 3, 4);List<Integer> distinct = numbers.stream().map( i -> i*i).distinct()                                         .collect(Collectors.toList());System.out.printf("Original List : %s,  Square Without duplicates :                   %s %n", numbers, distinct);Output :Original List : [9, 10, 3, 4, 7, 3, 4],  Square Without                                          duplicates : [81, 100, 9, 16, 49]

 

10.计算List中的元素的最大值，最小值，总和及平均值

//Get count, min, max, sum, and average for numbersList<Integer> primes = Arrays.asList(2, 3, 5, 7, 11, 13, 17, 19, 23, 29);IntSummaryStatistics stats = primes.stream().mapToInt((x) -> x)                                            .summaryStatistics();System.out.println("Highest prime number in List : " + stats.getMax());System.out.println("Lowest prime number in List : " + stats.getMin());System.out.println("Sum of all prime numbers : " + stats.getSum());System.out.println("Average of all prime numbers : " + stats.getAverage());Output : Highest prime number in List : 29Lowest prime number in List : 2Sum of all prime numbers : 129Average of all prime numbers : 12.9