10以内的简单计算

来源：互联网发布：网络诈骗要判几年编辑：程序博客网时间：2024/04/29 02:48
使用两个栈实现简单的数值计算
#define _CRT_SECURE_NO_WARNINGS#include <stdlib.h>#include<stdio.h>#include<string.h>#include<math.h>#define 输入合法  str1[i]>=48&&str1[i]<=57||str1[i]==42||str1[i]==43||str1[i]==45||str1[i]== 47#define SIZE 15char str1[SIZE], str2[SIZE], str3[SIZE];float str4[SIZE];int i = 0, j = 0, k = 0;float a=0,b=0, temp = 0;void main(){gets(str1);for (i = 0; i < strlen(str1); i++){if (输入合法){if (str1[i] >= 48 && str1[i] <= 57)//找出输入字符串中的数字并存储在数组str2里{str2[j] = str1[i];j++;}else if (str1[i] == 42 || str1[i] == 43 || str1[i] == 45 || str1[i] == 47)//找出输入字符串中的运算符号（+、-、*、/）{if (k == 0){str3[k] = str1[i];k++;}else{if (str1[i] == 42 || str1[i] == 47)//乘法和除法优先级高于加法和减法，直接写入数组str3{str3[k] = str1[i];k++;}else if (str1[i] == 43 || str1[i] == 45)//加法和减法需要再作判断{if (str3[k - 1] == 43 || str3[k - 1] == 45){str3[k] = str1[i];k++;}else{while (str3[k - 1] == 42 || str3[k - 1] == 47)//如果数组str3里最后一个运算符高于加法和减法，则高运算符复制到数组str2中，{str2[j] = str3[k - 1];j++;k--;}str3[k] = str1[i];k++;}}}}}else{goto ERROR;}}for (k =k- 1; k >= 0; k--){str2[j] = str3[k];//str3[k] = 0;j++;}//数组str2="123*45*6++"for (i = 0, k = 0,j=0; i < strlen(str1); i++){if (str2[i] >= 48 && str2[i] <= 57)//找出输入字符串中的数字并存储在数组str3里{str4[k] = str2[i]-48;k++;}else if (str2[i] == 42 || str2[i] == 43 || str2[i] == 45 || str2[i] == 47)//找出输入字符串中的运算符号（+、-、*、/）{if (str2[i] == 42){temp = str4[k - 1]  * str4[k - 2];k = k - 2;}else if (str2[i] == 43){temp = str4[k - 1] + str4[k - 2];k = k - 2;}else if (str2[i] == 45){temp = str4[k - 1] - str4[k - 2];k = k - 2;}else if (str2[i] == 47){/*a = str4[k - 1];b = str4[k - 2];*/temp = str4[k - 2] / str4[k - 1];k = k - 2;}str4[k] = temp;k++;}}printf("%.2f\n", temp);ERROR: printf("errorinput!\n");system("pause");}
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