【POJ 3641】Pseudoprime numbers
来源:互联网 发布:app制作软件哪个好 编辑:程序博客网 时间:2024/04/29 22:58
Pseudoprime numbers
Description
Fermat’s theorem states that for any prime number p and for any integer a > 1, ap = a (mod p). That is, if we raise a to the pth power and divide by p, the remainder is a. Some (but not very many) non-prime values of p, known as base-a pseudoprimes, have this property for some a. (And some, known as Carmichael Numbers, are base-a pseudoprimes for all a.)
Given 2 < p ≤ 1000000000 and 1 < a < p, determine whether or not p is a base-a pseudoprime.
Input
Input contains several test cases followed by a line containing “0 0”. Each test case consists of a line containing p and a.
Output
For each test case, output “yes” if p is a base-a pseudoprime; otherwise output “no”.
Sample Input
3 2
10 3
341 2
341 3
1105 2
1105 3
0 0
Sample Output
no
no
yes
no
yes
yes
#include<stdio.h>#include<string.h>long long quickcmp(long long i,long long j,long long k){ long long sum=1,base=i; while(j) { if(j&1) { sum=sum*base%k; } base=(base%k*base%k)%k; j>>=1; } return sum;}int prime(long long a ){ int i; if(a==2) return 1; for(i=2;i*i<=a;i++) if(a%i==0) return 0; return 1;}int main(){ long long p,a; while(scanf("%lld%lld",&p,&a)!=EOF&&(a||p)) { if(prime(p)) printf("no\n"); else { if(quickcmp(a,p,p)==a) printf("yes\n"); else printf("no\n"); } } return 0;}
- POJ-3641-Pseudoprime numbers
- POJ 3641-Pseudoprime numbers
- poj 3641 Pseudoprime numbers
- poj 3641 Pseudoprime numbers
- POJ 3641 Pseudoprime numbers
- poj 3641 Pseudoprime numbers
- POJ-3641 Pseudoprime numbers
- POJ 3641 Pseudoprime numbers
- 【POJ 3641】Pseudoprime numbers
- poj 3641 Pseudoprime numbers
- POJ-3641 Pseudoprime numbers
- Pseudoprime numbers POJ 3641
- poj 3641 Pseudoprime numbers
- poj 3641 Pseudoprime numbers
- POJ - 3641 Pseudoprime numbers
- 【 POJ 3641 】Pseudoprime numbers
- 【POJ 3641】Pseudoprime numbers
- 【POJ】[3641]Pseudoprime numbers
- android stuido搭建vlc流媒体播放环境
- javaee-mysql-jdbc中遇到的小问题一
- java编程---1、空心菱形
- 碰撞线框
- shell写俄罗斯方块(一)
- 【POJ 3641】Pseudoprime numbers
- java面试题
- 机房收费系统之报表设计器
- SAP HANA云平台YaaS,你不知道的三件事
- fedora 22 安装postgresql
- reactJS - 01初识
- 互联网协议入门(一)
- python核心编程第十一章练习
- 【杭电2052】Picture