hdoj 4006 The kth great number 【栈】

The kth great number

Time Limit: 2000/1000 MS (Java/Others)    Memory Limit: 65768/65768 K (Java/Others)
Total Submission(s): 9961    Accepted Submission(s): 3969

Problem Description

Xiao Ming and Xiao Bao are playing a simple Numbers game. In a round Xiao Ming can choose to write down a number, or ask Xiao Bao what the kth great number is. Because the number written by Xiao Ming is too much, Xiao Bao is feeling giddy. Now, try to help Xiao Bao.

 

Input

There are several test cases. For each test case, the first line of input contains two positive integer n, k. Then n lines follow. If Xiao Ming choose to write down a number, there will be an " I" followed by a number that Xiao Ming will write down. If Xiao Ming choose to ask Xiao Bao, there will be a "Q", then you need to output the kth great number.

 

Output

The output consists of one integer representing the largest number of islands that all lie on one line.

 

Sample Input

8 3I 1I 2I 3QI 5QI 4Q

 

Sample Output

123
Hint
Xiao  Ming  won't  ask  Xiao  Bao  the  kth  great  number  when  the  number  of  the  written number is smaller than k. (1=<k<=n<=1000000).
 

 开始想着从大到小，先K+大的数出栈，输出K大数，再把出栈的数进栈，如果k很大那不就抓瞎了，

》》脑子灵一点儿

代码：

 

#include<cstdio>#include<cstring>#include<queue>using namespace std;int main(){int n,k,a,b,c;char str[10];while(~scanf("%d%d",&n,&k)){priority_queue<int,vector<int>,greater<int> > que;for(int i=0;i<n;i++){scanf("%s",str);if(strcmp(str,"I")==0){getchar();scanf("%d",&a);que.push(a); if(que.size()>k)//只保留k个最大的数，前面小的数都出栈 que.pop();}else{printf("%d\n",que.top());} } }return 0;}