TOJ 2977.Eight

题目链接 : http://acm.tju.edu.cn/toj/showp2977.html

Description

8-ball is a billiards competition rules. 7 red balls on the table, 7 yellow balls and a black ball, of course, a white ball. For this problem, we use the following simplified rules: red, yellow two players take turns hitting the ball by using the white ball, red player hits the red balls and yellow player hits the yellow balls.

If the player has hit all his 7 balls and got 7 points, he can hit the black ball, and he will win if it scores. If the player makes the black ball score before he hit all his 7 balls he will lose. If the player accidentally scored the opponent’s ball, goal is still valid.

Now give you the order of the balls being scored (other than the white ball), and who reached the black ball, your task is to determine which side is the winner.

Assuming a black ball and other ball cannot be scored at the same time.
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没什么好说的，一般玩的台球的规则就是这样的。

#include <stdio.h>#include <iostream>using namespace std;int main(){    int y,r,n;    bool win;    char input;    while(scanf("%d",&n) && n){        y=r=0;        win=false;        for(int i=0;i<n;i++){            cin>>input;            if(input=='Y')                y++;            else if(input == 'R')                r++;            else if(r==7&&input=='B' || y<7&&input=='L'){                win=true;            }        }        if(win)            printf("Red\n");        else             printf("Yellow\n");    } }