【leetcode Database】181. Employees Earning More Than Their Managers

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题目：

The Employee table holds all employees including their managers. Every employee has an Id, and there is also a column for the manager Id.

+----+-------+--------+-----------+| Id | Name  | Salary | ManagerId |+----+-------+--------+-----------+| 1  | Joe   | 70000  | 3         || 2  | Henry | 80000  | 4         || 3  | Sam   | 60000  | NULL      || 4  | Max   | 90000  | NULL      |+----+-------+--------+-----------+

Given the Employee table, write a SQL query that finds out employees who earn more than their managers. For the above table, Joe is the only employee who earns more than his manager.

+----------+| Employee |+----------+| Joe      |+----------+

解析：本题可以使用自连接来做。声明Employee表的两个别名e1和e2，然后select e1的ManagerId字段与e2的Id字段相等，且e1的Salary大于e2的Salary。代码如下：

# Write your MySQL query statement belowSELECT e1.Name AS Employee FROM Employee AS e1,Employee AS e2 WHERE e1.ManagerId = e2.Id AND e1.Salary > e2.Salary;

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