Light OJ 1116 Ekka Dokka

1116 - Ekka Dokka

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Time Limit: 2 second(s)Memory Limit: 32 MB

Ekka and his friend Dokka decided to buy a cake. They both love cakes and that's why they want to share the cake after buying it. As the name suggested that Ekka is very fond of odd numbers and Dokka is very fond of even numbers, they want to divide the cake such that Ekka gets a share of N square centimeters and Dokka gets a share of M square centimeters where N is odd and M is even. Both N and M are positive integers.

They want to divide the cake such that N * M = W, where W is the dashing factor set by them. Now you know their dashing factor, you have to find whether they can buy the desired cake or not.

Input

Input starts with an integer T (≤ 10000), denoting the number of test cases.

Each case contains an integer W (2 ≤ W < 2⁶³). And W will not be a power of 2.

Output

For each case, print the case number first. After that print "Impossible" if they can't buy their desired cake. If they can buy such a cake, you have to print N and M. If there are multiple solutions, then print the result where M is as small as possible.

Sample Input

Output for Sample Input

3

10

5

12

Case 1: 5 2

Case 2: Impossible

Case 3: 3 4

 暴力过一遍，编译器出问题了，结果一直不对，感觉写的问题，就试试着交了一下，AC了。。。

#include<stdio.h>#include<string.h>#include<algorithm>#define LL long long  using namespace std;int main(){int t;LL w,i,k,l,n,m;scanf("%d",&t);k=1;while(t--){scanf("%lld",&w);if(w%2){printf("Case %lld: Impossible\n",k++);}else{for(i=2;i<=w;i++)    {   if(w%i==0&&(w/i)%2)   {  n=w/i;  break;   }    }    printf("Case %lld: %lld %lld\n",k++,n,i);}}return 0;}