题目216 A problem is easy

     已AC代码：

#include<cstdio>main(){    int n,i,t;    scanf("%d",&t);    while(t--)    {        int s=0;        scanf("%d",&n);        for(i=1;(i+1)*(i+1)<=n+1;i++)        {            if((n+1)%(i+1)==0)            s++;        }        printf("%d\n",s);    }    }