HDU 5443 The Water Problem

The Water Problem

Problem Description

In Land waterless, water is a very limited resource. People always fight for the biggest source of water. Given a sequence of water sources with a1,a2,a3,…,an representing the size of the water source. Given a set of queries each containing 2 integers l and r, please find out the biggest water source between al and ar.

Input

First you are given an integer T(T≤10) indicating the number of test cases. For each test case, there is a number n(0≤n≤1000) on a line representing the number of water sources. n integers follow, respectively a1,a2,a3,…,an, and each integer is in {1,…,106}. On the next line, there is a number q(0≤q≤1000) representing the number of queries. After that, there will be q lines with two integers l and r(1≤l≤r≤n) indicating the range of which you should find out the biggest water source.

Output

For each query, output an integer representing the size of the biggest water source.

Sample Input

3
1
100
1
1 1
5
1 2 3 4 5
5
1 2
1 3
2 4
3 4
3 5
3
1 999999 1
4
1 1
1 2
2 3
3 3

Sample Output

100
2
3
4
4
5
1
999999
999999
1

很水的一道题目，题意是找出给定范围内的最大值

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AC

#include <cstdio>int main(){    int T;    scanf("%d",&T);    while(T--)    {        int n;        scanf("%d",&n);        long int a[n];        for(int i=0; i<n; i++)            scanf("%ld",&a[i]);        int q;        scanf("%d",&q);        int x,y;        for(int i=1; i<=q; i++)        {            scanf("%d%d",&x,&y);            long int maxn=0;            if(x==y)                maxn=a[x-1];            else            {                for(int j=x-1; j<y; j++)                {                    if(j==x-1)                        maxn=a[j];                    else if(a[j]>maxn)                        maxn=a[j];                }            }            printf("%ld\n",maxn);        }    }    return 0;}