Double

Doubles

Time Limit:1000MS    Memory Limit:10000KB    64bit IO Format:%lld & %llu

Description
As part of an arithmetic competency program, your students will be given randomly generated lists of from 2 to 15 unique positive integers and asked to determine how many items in each list are twice some other item in the same list. You will need a program to help you with the grading. This program should be able to scan the lists and output the correct answer for each one. For example, given the list

1 4 3 2 9 7 18 22

your program should answer 3, as 2 is twice 1, 4 is twice 2, and 18 is twice 9.
Input
The input will consist of one or more lists of numbers. There will be one list of numbers per line. Each list will contain from 2 to 15 unique positive integers. No integer will be larger than 99. Each line will be terminated with the integer 0, which is not considered part of the list. A line with the single number -1 will mark the end of the file. The example input below shows 3 separate lists. Some lists may not contain any doubles.

Output

The output will consist of one line per input list, containing a count of the items that are double some other item.

Sample Input

1 4 3 2 9 7 18 22 02 4 8 10 07 5 11 13 1 3 0-1

Sample Output

320

题目为查找倍数的个数，输入多组数据，以-1截止，每组数据以数据0为截止。

#include<stdio.h>int main(){int a[20],i,j,n,s;scanf("%d",&a[0]); //输入第一个数while(a[0]!=-1)  //判断是否为-1{n=0;s=0;while(a[n]!=0){n++;scanf("%d",&a[n]);}for(i=0;i<n;i++)    //枚举{  for(j=i+1;j<n;j++)  //从i+1开始{if(a[j]==2*a[i]||a[i]==2*a[j]) //判断a[j]是否为a[i]的2倍或a[i]为a[j]的2倍s=s+1;    //是的话个数+1}}printf("%d\n",s);scanf("%d",&a[0]);//输入第一个数}return 0;}