HDU 2817 A sequence of numbers (数学+快速幂)

Problem Description

Xinlv wrote some sequences on the paper a long time ago, they might be arithmetic or geometric sequences. The numbers are not very clear now, and only the first three numbers of each sequence are recognizable. Xinlv wants to know some numbers in these sequences, and he needs your help.


Input
The first line contains an integer N, indicting that there are N sequences. Each of the following N lines contain four integers. The first three indicating the first three numbers of the sequence, and the last one is K, indicating that we want to know the K-th numbers of the sequence.

You can assume 0 < K <= 10^9, and the other three numbers are in the range [0, 2^63). All the numbers of the sequences are integers. And the sequences are non-decreasing.


Output
Output one line for each test case, that is, the K-th number module (%) 200907.


Sample Input
2
1 2 3 5
1 2 4 5


Sample Output
5
16


Source

2009 Multi-University Training Contest 1 - Host by TJU

题意： 

    给你数列的前三个数a、b、c,判断这个数列是等差数列还是等比数列，然后求数列的第K个值，，，最后对200907取模，

思路：

  先根据前三个数判断数列，再用等差或者等比数列公式求第k个值，，取模需要使用快速幂。。

以下AC代码：

#include<stdio.h>#define mod 200907long long QucikMod(long long a,long long b){    long long temp=1;    a=a%mod;    while(b>0)    {        if(b%2==1)        temp=(temp*a)%mod;        b=b/2;        a=(a*a)%mod;    }    return temp;}int main(){    long long t,a,b,c,q,d,k,sum;    scanf("%I64d",&t);    while(t--)    {    scanf("%I64d%I64d%I64d%I64d",&a,&b,&c,&k);    if(c-b==b-a)    {        d=b-a;        sum=(a%mod+(k-1)*d%mod)%mod;    }    else    {        q=b/a;        sum=a*QucikMod(q,k-1)%mod;    }    printf("%I64d\n",sum);    }    return 0;}