使用shell自动部署tomcat项目

来源:互联网 发布:相似矩阵 编辑:程序博客网 时间:2024/06/16 20:30

由于测试服务器经常需要更新,觉得太麻烦就写了个shell脚本,记录下来仅供大家参考

#!/bin/bash#------自动部署多个tomcat项目脚本------#1.删除部署目录下已存在的项目#2.解压war包到对应目录下#3.重新启动tomcat服务器#--------------------------------------home_dir=/home/t0mcat#tomcat目录soa_tomcat_path=/opt/software/apache-tomcat-7.0.64_SOA#部署目录soa_deployment_path=/opt/software/web/dev/yiweinet-soa#war包名称soa_war=business-soa.warmer_tomcat_path=/opt/software/apache-tomcat-7.0.64_MERCHANTmer_deployment_path=/opt/software/web/dev/business-merchantmer_war=business-merchant.war#get war and return pathfindAllWar(){  cd $home_dir  v_war_file_list=$(find -name "*.war")  echo "war list:"  ls $v_war_file_list}process(){for i in $(findAllWar)  do    v_file_path=$i    #echo $v_file_path      v_file_name=${v_file_path##*/}    echo $v_file_name      if [ $v_file_name = $soa_war ]     then        operTomcat $soa_war $soa_deployment_path $soa_tomcat_path    fi    if [ $v_file_name = $mer_war ]     then        operTomcat $mer_war $mer_deployment_path $mer_tomcat_path    fi done}operTomcat() {        stopTomcat $3        #get first param length    v_file_length=${#1}        #get file name(1 is first param)    v_file_name=${1:0:$[ $v_file_length - 4 ]}        #del and move war    cd $2    rm -rf $v_file_name*             jar xvf ${home_dir}/$1     startTomcat $3  }stopTomcat() {    cd $1"/bin"    ./shutdown.sh    #rm -rf $1"/logs/"*    echo "$1 shutdown over"    } startTomcat() {    cd $1"/bin"    ./startup.sh    echo "$1 start over"  }  echo "start"  process  echo "end"

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