PAT 1065. A+B and C (64bit) (20)

         

题目描述：Given three integers A, B and C in [-2⁶³, 2⁶³], you are supposed to tell whether A+B > C.

Input Specification:

The first line of the input gives the positive number of test cases, T (<=10). Then T test cases follow, each consists of a single line containing three integers A, B and C, separated by single spaces.

Output Specification:

For each test case, output in one line "Case #X: true" if A+B>C, or "Case #X: false" otherwise, where X is the case number (starting from 1).

Sample Input:

31 2 32 3 49223372036854775807 -9223372036854775808 0

Sample Output:

Case #1: falseCase #2: trueCase #3: false

    出题人的本意应该是让我们进行溢出判断，但是这里可以将变量直接定义为long double类型。

#include <iostream>using namespace std;int main(){    long double  a,b;    long double  c;    int n;    cin>>n;    for(int i=0;i<n;i++)    {        cin>>a>>b>>c;        cout<<"Case #"<<i+1<<": ";        if(a-c+b>0)            cout<<"true";        else cout<<"false";        cout<<endl;    }    return 0;}