统计数字类型的String数组中各个元素的个数

public class Test {


public static void main(String[] args) {


String[] str = { "1", "2", "2", "2", "5", "5", "5", "4", "3", "3" };

先排序在操作。
String in = "";
for (int i = 0; i < str.length; i++) {
for (int j = i + 1; j < str.length; j++) {
if (Integer.parseInt(str[i]) > Integer.parseInt(str[j])) {
in = str[j];
str[j] = str[i];
str[i] = in;
}
}


}
for (int i = 0; i < str.length; i++) {
System.out.println(str[i]);
}
for (int i = 0; i < str.length; i++) {


for (int j = i; j < str.length; j++) {
if (Integer.parseInt(str[j]) > Integer.parseInt(str[i])) {
System.out.println(str[i] + "..........." + (j - i));
i=j-1;
break;
}
}
if (Integer.parseInt(str[i]) == Integer.parseInt(str[str.length-1])) {
 
System.out.println(str[i] + "..........." + (str.length-i));
break;
}
}


}

}

运行结果

1
2
2
2
3
3
4
5
5
5
1...........1
2...........3
3...........2
4...........1
5...........3