POJ 1995 Raising Modulo Numbers
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Raising Modulo Numbers
Time Limit: 1000MS Memory Limit: 30000KTotal Submissions: 6648 Accepted: 3958
Description
People are different. Some secretly read magazines full of interesting girls' pictures, others create an A-bomb in their cellar, others like using Windows, and some like difficult mathematical games. Latest marketing research shows, that this market segment was so far underestimated and that there is lack of such games. This kind of game was thus included into the KOKODáKH. The rules follow:
Each player chooses two numbers Ai and Bi and writes them on a slip of paper. Others cannot see the numbers. In a given moment all players show their numbers to the others. The goal is to determine the sum of all expressions AiBifrom all players including oneself and determine the remainder after division by a given number M. The winner is the one who first determines the correct result. According to the players' experience it is possible to increase the difficulty by choosing higher numbers.
You should write a program that calculates the result and is able to find out who won the game.
Each player chooses two numbers Ai and Bi and writes them on a slip of paper. Others cannot see the numbers. In a given moment all players show their numbers to the others. The goal is to determine the sum of all expressions AiBifrom all players including oneself and determine the remainder after division by a given number M. The winner is the one who first determines the correct result. According to the players' experience it is possible to increase the difficulty by choosing higher numbers.
You should write a program that calculates the result and is able to find out who won the game.
Input
The input consists of Z assignments. The number of them is given by the single positive integer Z appearing on the first line of input. Then the assignements follow. Each assignement begins with line containing an integer M (1 <= M <= 45000). The sum will be divided by this number. Next line contains number of players H (1 <= H <= 45000). Next exactly H lines follow. On each line, there are exactly two numbers Ai and Bi separated by space. Both numbers cannot be equal zero at the same time.
Output
For each assingnement there is the only one line of output. On this line, there is a number, the result of expression
(A1B1+A2B2+ ... +AHBH)mod M.
Sample Input
31642 33 44 55 63612312374859 30293821713 18132
Sample Output
21319513
有的人爱看片儿、有的人爱在地窖里造原子弹、有的人爱用Windows,我爱计算(A1B1+A2B2+ … +AHBH)mod M,真的不是很懂你们出题人。纯快速幂。为什么32位机用long long老是各种毛病?__int64就没事,但是某个OJ不能用__int64,搞得我现在只敢用long long了,这次干脆不输出了,找了半天没有bug,改成__int64一切正常。然后交了。直接AC。百思不得其姐姐。
#include<stdio.h>long long fff(long long x,long long y,long long z){long long ans=1;x=x%z;while(y){if(y%2==1)ans=(ans*x)%z;x=(x*x)%z;y=y/2;}return ans;}int main(){int t;scanf("%d",&t);long long i,m,n,a,b,ans;while(t--){ans=0;scanf("%lld%lld",&m,&n);for(i=0;i<n;i++){scanf("%lld%lld",&a,&b);ans=(ans+fff(a,b,m))%m;}printf("%lld\n",ans);}return 0;}
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