VivoParc
来源:互联网 发布:淘宝售后率高 编辑:程序博客网 时间:2024/06/05 14:33
VivoParc
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题意:给n个点和多条边,要求在n个点填充4种颜色之一,使得相邻点颜色不同
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解法:又题意和定理知道一定有解,那么直接暴力就行了
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#include <iostream>#include <stdio.h>#include <stdlib.h>#include <string.h>using namespace std;#pragma comment(linker, "/STACK:1024000000,1024000000")int n, m, x, y, f[3000], tot;bool flag[2000][2000];char c[2000];bool dfs(int x) { bool fuck[5]; for (int i = 1; i <= 4; i++) fuck[i] = true; for (int i = 1; i <= n; i++) if (flag[x][i]) { if (f[i] == 1) fuck[1] = false; if (f[i] == 2) fuck[2] = false; if (f[i] == 3) fuck[3] = false; if (f[i] == 4) fuck[4] = false; } for (int k = 1; k <= 4; k++) if (fuck[k]) { f[x] = k; bool cur = true; for (int i = 1; i <= n; i++)if (flag[x][i] && f[i] == 0 && !dfs(i)) { cur = false; break; } if (cur) return true; } f[x] = 0; return false;}int main() { tot = 0; while (scanf("%d", &n) != EOF) { tot++; memset(flag, 0, sizeof(flag)); memset(f, 0, sizeof(f)); char cc; scanf("%c", &cc); while (1) { std::cin.getline(c, 1024); if (strlen(c) == 0) break; sscanf(c, "%d-%d", &x, &y); flag[x][y] = true; flag[y][x] = true; } for (int i = 1; i <= n; i++) if (f[i] == 0) { dfs(i); } //if (tot >= 1) cout << endl; for (int i = 1; i <= n; i++) { cout << i << " " << f[i] << endl; } cout << endl; }}
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