Oulipo_poj3461_kmp
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Description
The French author Georges Perec (1936–1982) once wrote a book, La disparition, without the letter ‘e’. He was a member of the Oulipo group. A quote from the book:
Tout avait Pair normal, mais tout s’affirmait faux. Tout avait Fair normal, d’abord, puis surgissait l’inhumain, l’affolant. Il aurait voulu savoir où s’articulait l’association qui l’unissait au roman : stir son tapis, assaillant à tout instant son imagination, l’intuition d’un tabou, la vision d’un mal obscur, d’un quoi vacant, d’un non-dit : la vision, l’avision d’un oubli commandant tout, où s’abolissait la raison : tout avait l’air normal mais…
Perec would probably have scored high (or rather, low) in the following contest. People are asked to write a perhaps even meaningful text on some subject with as few occurrences of a given “word” as possible. Our task is to provide the jury with a program that counts these occurrences, in order to obtain a ranking of the competitors. These competitors often write very long texts with nonsense meaning; a sequence of 500,000 consecutive ‘T’s is not unusual. And they never use spaces.
So we want to quickly find out how often a word, i.e., a given string, occurs in a text. More formally: given the alphabet {‘A’, ‘B’, ‘C’, …, ‘Z’} and two finite strings over that alphabet, a word W and a text T, count the number of occurrences of W in T. All the consecutive characters of W must exactly match consecutive characters of T. Occurrences may overlap.
Input
The first line of the input file contains a single number: the number of test cases to follow. Each test case has the following format:
One line with the word W, a string over {‘A’, ‘B’, ‘C’, …, ‘Z’}, with 1 ≤ |W| ≤ 10,000 (here |W| denotes the length of the string W).
One line with the text T, a string over {‘A’, ‘B’, ‘C’, …, ‘Z’}, with |W| ≤ |T| ≤ 1,000,000.
Output
For every test case in the input file, the output should contain a single number, on a single line: the number of occurrences of the word W in the text T.
题意
给出t对字符串,求a串在b串中的出现次数
题解
直接作t次kmp,求匹配数
不要问我为什么用p,c++字符串太蛋疼
Code
var p:array[1..100000]of longint; t:longint;function kmp(var a,b:ansistring):longint;var i,j,n,m:longint;begin n:=length(a); m:=length(b); j:=0; kmp:=0; for i:=1 to n do begin while (a[i]<>b[j+1])and(j>0) do j:=p[j]; if (a[i]=b[j+1]) then inc(j); if (j=m) then begin inc(kmp); j:=p[j]; end; end;end;procedure init;var i,j,v,n,m:longint; a,b:ansistring;begin readln(t); for v:=1 to t do begin readln(b); readln(a); m:=length(b); fillchar(p,sizeof(p),0); p[1]:=0; j:=0; for i:=2 to m do begin while (b[i]<>b[j+1])and(j>0) do j:=p[j]; if (b[i]=b[j+1]) then inc(j); p[i]:=j; end; writeln(kmp(a,b)); end;end;begin init;end.
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