python pygame 复刻小游戏 躲避方块

新上手pygame，断断续续学习python也有一短时间了，心血来潮复刻一个小游戏（其实差的不少）。

界面就是这样：

游戏目标也很简单：四色方框来回碰撞移动，控制黑色方框躲避他们，得分是坚持多少的秒数。

贴代码，新手水平，可以打磨的地方还有很多

import sys,pygame,timefrom pygame.locals import *pygame.init()class box(object):    """this produce a box which may block the controller"""    def __init__(self, x, y, color, hor, ver, box_len):        """x and y as the position of box. ver is for vertical, hor is for horizontal. those are the moving speed of box.        box_len is the size"""        self.x = x        self.y = y        self.color = color        self.ver = ver        self.hor = hor        self.length = box_len        pygame.draw.rect(screen, self.color, (self.x, self.y, self.length, self.length), 0)    def move(self):        if self.x < 0 or self.x > 500:            self.hor = -self.hor        if self.y < 0 or self.y > 400:            self.ver = -self.ver        self.x += self.hor        self.y += self.ver        pygame.draw.rect(screen, self.color, (self.x, self.y, self.length, self.length), 0)            def box_R_xy(self):        return((self.x, self.y, self.length))class controller(object):    """this is what the mouse control"""    #----------------------------------------------------------------------    def __init__(self,ctl_len, color):        """Constructor"""        self.x = 0        self.y = 0        self.length = ctl_len        self.color = color    #----------------------------------------------------------------------    def draw_controller(self):        MOS_x, MOS_y = pygame.mouse.get_pos()        #check the border value        if MOS_x - self.length/2 < 0:            MOS_x = self.length/2        if MOS_x + self.length/2 > 600:            MOS_x = 600 - self.length/2        if MOS_y - self.length/2 < 0:            MOS_y = self.length/2        if MOS_y + self.length/2 > 500:            MOS_y = 500 - self.length/2        self.x = MOS_x        self.y = MOS_y                pygame.draw.rect(screen, self.color, (MOS_x-self.length/2, MOS_y-self.length/2, self.length, self.length), 0)        def ctl_R_xy(self):        """return x and y of controller"""        return((self.x, self.y, self.length))        class timer(object):    #use time.clock as a time counting tool    def __init__(self):        self.begin = True        self.beginTime = 0        self.stopTime = 0    def start(self):        if self.begin:            self.beginTime = time.clock()            self.begin = False        return time.clock() - self.beginTime    def stop(self):        self.stopTime = self.start()        self.beginTime = 0        self.begin = True        return self.stopTimedef cld_dtcn(controller, box):    Cx1,Cy1,Clen = controller.ctl_R_xy()    Bx1,By1,Blen = box.box_R_xy()    #check whether the four points of ctl in the box area     if(Cx1-Clen/2 in range(Bx1, Bx1+Blen)) and (Cy1 - Clen/2 in range(By1, By1 + Blen)):        return True    if(Cx1+Clen/2 in range(Bx1, Bx1+Blen)) and (Cy1 - Clen/2 in range(By1, By1 + Blen)):        return True    if(Cx1-Clen/2 in range(Bx1, Bx1+Blen)) and (Cy1 + Clen/2 in range(By1, By1 + Blen)):        return True    if(Cx1+Clen/2 in range(Bx1, Bx1+Blen)) and (Cy1 + Clen/2 in range(By1, By1 + Blen)):        return True    return Falsedef print_text(font, text, pos, color):    imgText = font.render(text, True, color)    screen.blit(imgText, pos)                        # main beginscreen = pygame.display.set_mode((600,500))pygame.display.set_caption("Escaping the boxes")# default datawhite =255,255,255black = 0,0,0blue = 0,0,255red = 255,0,0green = 0,255,0yellow = 255,255,0purple = 255,0,255cyan1 = 0,255,255myFont = pygame.font.Font(None, 20)#length of controller lengthctl_len =  40#length of boxesbox_len = 100#initialize boxesb1 = box(0,0, blue, 2,1,box_len)b2 = box(500,0,red, 1,2,box_len)b3 = box(400,0,green, 1,1,box_len)b4 = box(500,400,yellow,3,1,box_len)#initialize controllerctl = controller(ctl_len, black)#about timebestTime = 0currentTime = 0tk = timer()while True:    pygame.mouse.set_visible(False)    for event in pygame.event.get():        if event.type == QUIT:            sys.exit()        keys = pygame.key.get_pressed()        if keys[K_ESCAPE]:            sys.exit()    currentTime = tk.start()    screen.fill(cyan1)    print_text(myFont, "Best Score: " + str(bestTime), (0,0), black)    print_text(myFont, "Current Score: " + str(currentTime), (0,40), black)    ctl.draw_controller()        b1.move()    b2.move()    b3.move()    b4.move()    if cld_dtcn(ctl,b1) or cld_dtcn(ctl,b2) or cld_dtcn(ctl,b3) or cld_dtcn(ctl,b4):        stopTime = tk.stop()        if bestTime < stopTime:            bestTime = stopTime    pygame.display.update()    

因为比较懒，注释写的少，应该都还挺清楚的。

最有技巧的地方在碰撞检测，刚刚上手，还没看到pygame内部有没有碰撞检测的地方。所以就用黑色方块的四个角的坐标与其他的方块对比，如果控制的是圆形的话恐怕要算圆心距离了。暂时我也想不到其他的好办法。

timer()对象用来检测时间，time.clock()是一个全局的变量。不好控制，做定时器的话应该还有更好的方法。

时间关系，就先以上这些。

PS: 《python游戏 编程入门》这本书的错误不少，建议大家不要买这本书。

https://book.douban.com/subject/26311697/