[leetcode] 313. Super Ugly Number
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Write a program to find the nth super ugly number.
Super ugly numbers are positive numbers whose all prime factors are in the given prime list primes
of size k
. For example, [1, 2, 4, 7, 8, 13, 14, 16, 19, 26, 28, 32]
is the sequence of the first 12 super ugly numbers given primes
= [2, 7, 13, 19]
of size 4.
Note:
(1) 1
is a super ugly number for any given primes
.
(2) The given numbers in primes
are in ascending order.
(3) 0 < k
≤ 100, 0 < n
≤ 106, 0 < primes[i]
< 1000.
解法一:
完全思路,看的大神的解法。维护一个数组idx,保存当前的元素下一次应该与res里的哪一个元素相乘。如果是最小的元素,则更新idx。
class Solution {public: int nthSuperUglyNumber(int n, vector<int>& primes) { vector<int> res(1,1), idx(primes.size(),0); while(res.size()<n){ vector<int> tmp; int mn = INT_MAX; for(int i=0; i<primes.size();i++) tmp.push_back(res[idx[i]]*primes[i]); for(int i=0; i<primes.size();i++) mn = min(mn,tmp[i]); for(int i=0; i<primes.size();i++){ if(tmp[i]==mn) ++idx[i]; } res.push_back(mn); } return res.back(); }};
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