UVA-340
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#include <algorithm>
#include <iostream>
#include <utility>
#include <cstring>
#include <cstdlib>
#include <cstdio>
#include <deque>
#include <string>
#include <vector>
#include <cmath>
#include <stack>
#include <queue>
#include <map>
#include <set>
using namespace std;
#define mm(a,i) memset(a, i, sizeof(a));
#define LL long long
#define Mod 1000000007
#define SC_C(s) scanf("%c", &s)
#define SC(a) scanf("%d", &a)
#define SCC(a,b) scanf("%d %d", &a, &b)
#define SCCC(a,b,c) scanf("%d %d %d", &a, &b, &c)
#define FXA(i,a,n) for(i=a; i<n; i++)
#define FDA(i,a,n) for(i=a; i>n; i++)
#define FXDA(i,a,n) for(i=a; i<=n; i++)
#define FDDA(i,a,n) for(i=a; i>=n; i++)
#define FXB(i,a,n) for(i=a; i<n; i--)
#define FDB(i,a,n) for(i=a; i>n; i--)
#define FXDB(i,a,n) for(i=a; i<=n; i--)
#define FDDB(i,a,n) for(i=a; i>=n; i--)
#define PF(n) printf("%d\n", n);
#define PFF(n,m) printf("%d %d\n", n, m);
#define PFFF(x,y,z) printf("%d %d %d\n", x, y, z);
#define PF_Case(i) printf("Case %d:\n",i);
#define PF_C(i) printf("%d:\n",i);
#define PF_L(x) printf("%I64d\n",x);
#define IN freopen("D:\\in.txt","r",stdin);
#define MAX(a,b) a>b?a:b
#define MIN(a,b) a<b?a:b
int maxx = 999999999;
int minn = -999999999;
bool flag;
int i,j,k,T,ans,sum,m,n,cnt;
//string s;
int minn = -999999999;
bool flag;
int i,j,k,T,ans,sum,m,n,cnt;
//string s;
char* rev = "A 3 HIL JM O 2TUVWXY51SE Z 8 ";
char* msg[] = {"not a palindrome", "a regular palindrome", "a mirrored string", "a mirrored palindrome"};
char r(char ch) {
if(isalpha(ch)) return rev[ch - 'A'];
return rev[ch - '0' + 25];
}
int main() {
#ifndef ONLINE_JUDGE
IN
#endif // ONLINE_JUDGE
int n, a[1005], b[1005];
int kase = 0;
while(scanf("%d", &n) == 1 && n) { //n=0时输入结束
printf("Game %d:\n", ++kase);
for(int i = 0; i < n; i++) scanf("%d", &a[i]);
for(;;) {
int A = 0, B = 0;
for(int i = 0; i < n; i++) {
scanf("%d", &b[i]);
if(a[i] == b[i]) A++;
}
if(b[0] == 0) break; //正常的猜测序列不会有0,所以只判断第一个数是否为0即可
for(int d = 1; d <= 9; d++) {
int c1 = 0, c2 = 0; //统计数字d在答案序列和猜测序列中各出现多少次
for(int i = 0; i < n; i++) {
if(a[i] == d) c1++;
if(b[i] == d) c2++;
}
if(c1 < c2) B += c1;
else B += c2;
}
printf(" (%d,%d)\n", A, B-A);
}
}
return 0;
}
char* msg[] = {"not a palindrome", "a regular palindrome", "a mirrored string", "a mirrored palindrome"};
char r(char ch) {
if(isalpha(ch)) return rev[ch - 'A'];
return rev[ch - '0' + 25];
}
int main() {
#ifndef ONLINE_JUDGE
IN
#endif // ONLINE_JUDGE
int n, a[1005], b[1005];
int kase = 0;
while(scanf("%d", &n) == 1 && n) { //n=0时输入结束
printf("Game %d:\n", ++kase);
for(int i = 0; i < n; i++) scanf("%d", &a[i]);
for(;;) {
int A = 0, B = 0;
for(int i = 0; i < n; i++) {
scanf("%d", &b[i]);
if(a[i] == b[i]) A++;
}
if(b[0] == 0) break; //正常的猜测序列不会有0,所以只判断第一个数是否为0即可
for(int d = 1; d <= 9; d++) {
int c1 = 0, c2 = 0; //统计数字d在答案序列和猜测序列中各出现多少次
for(int i = 0; i < n; i++) {
if(a[i] == d) c1++;
if(b[i] == d) c2++;
}
if(c1 < c2) B += c1;
else B += c2;
}
printf(" (%d,%d)\n", A, B-A);
}
}
return 0;
}
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