HDOJ 5832 A water problem（高精度 大数取模）

A water problem

Time Limit: 5000/2500 MS (Java/Others)    Memory Limit: 65536/65536 K (Java/Others)
Total Submission(s): 826    Accepted Submission(s): 428

Problem Description

Two planets named Haha and Xixi in the universe and they were created with the universe beginning.

There is 73 days in Xixi a year and 137 days in Haha a year.

Now you know the days N after Big Bang, you need to answer whether it is the first day in a year about the two planets.

 

Input

There are several test cases(about 5 huge test cases).

For each test, we have a line with an only integer N(0≤N), the length of N is up to 10000000.

 

Output

For the i-th test case, output Case #i: , then output "YES" or "NO" for the answer.

 

Sample Input

100010333

 

Sample Output

Case #1: YESCase #2: YESCase #3: NO

 

Author

UESTC

 

Source

2016中国大学生程序设计竞赛 - 网络选拔赛 

思路：

这道题的题意很清楚，就是让你求73和137的的公倍数。因为73和137的最小公倍数是10001，所以其实也就是求这个数能不能模10001余0。但是由于输入的数是10000000位的数，用long long来装是肯定不行的，所以考虑用高精度。套用一个大数取余的模板

就可以。这里选择手动大数取模。

代码：

#include<iostream>  #include<string>  #include<cstdio>  int const maxn=10000000+5;  char str[maxn];  using namespace std;  int main(){     //freopen("in.txt","r",stdin);      int t=0;      while(scanf("%s",str)!=EOF)      {          t++;          int i;          int rem=0;          for(i=0;str[i];i++){              rem=rem*10+str[i]-'0';              rem=rem%10001;          }          printf("Case #%d: ",t);          if(rem==0) printf("YES\n");          else printf("NO\n");      }  }