暑期dp46道(42)--HDOJ 1789 Doing Homework again 贪心
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题目链接:HDOJ 1789
题意:和状压dp那个类似,不过这个和那个区别就是 这个每门作业都只要一天就可以完成,而且一旦没有在规定期限内完成就直接罚分,一次性罚完,所以这题可以直接排序后贪心做(做完每们作业所需时间(代价相同),贪心解这类题目较多)
代码:
#include<cstdio>#include<cstring>#include<string>#include<queue>#include<algorithm>#include<iostream>#include<stack>#include<queue>#include<limits>using namespace std;#define debug 0#define Max(a,b) ((a>b)?a:b)#define M(a) memset(a,0,sizeof(a))#define REP(o) for(int i=1;i<=o;i++)const int maxn = 1000 + 5;struct R{int time;int score;}r[maxn];int n, caseNum, total;bool vis[10010];bool cmp(const R a, const R b){//按分数递减,分数相同按时间递增排序if (a.score == b.score)return a.time<b.time;returna.score>b.score;}void Do(){int sum = 0, j;sort(r + 1, r + n + 1, cmp);for (int i = 1; i <= n; i++){for (j = r[i].time; j>0; j--)//望前查找 若有的时间还未被占 把这一天记为已访问{if (!vis[j]){vis[j] = 1;break;}}if (!j)//如果 j = 0把这个分数加到罚分里{sum += r[i].score;}}printf("%d\n", sum);}int main(){#if debugfreopen("in.txt", "r", stdin);#endif // debugwhile (~scanf("%d", &caseNum)){while (caseNum--){M(vis);scanf("%d", &n);REP(n){scanf("%d", &r[i].time);}REP(n){scanf("%d", &r[i].score);}Do();}}return 0;}
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