HDU 1022 Train Problem I 栈
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这题......一看图就能看出来用啥做了啊啊= =这个图是多么经典的讲栈的图......好吧,先看下题,输入火车进入的顺序,问出去的顺序是否可以达成............好吧,头文件默默打上<stack>开始做题吧= =
不过这题不只是要判断状态,还要把火车变成这个状态的步骤记录下来,一开始写的时候忽略了判断状态这点......结果写完步骤才发现得先判断,好吧,于是我“巧妙”的复制粘贴了一下╮(╯_╰)╭,代码行数瞬间变成两倍了,虽然有些繁琐,不过A了就好~
下面AC代码:
#include<iostream>#include<cstdio>#include<cstring>#include<algorithm>#include<stack>using namespace std;char a[10005];char target[10005];stack<char>track;int main(){ int n; char t; int i,j; while(scanf("%d",&n)!=EOF) { while(!track.empty()) { track.pop(); } scanf("%s",a); scanf("%s",target); j=0; for(i=0;i<n;i++) { track.push(a[i]); if(a[i]==target[j]) { j++; track.pop(); if(!track.empty()) t=track.top(); while(!track.empty()) { if(t==target[j]) { j++; track.pop(); if(!track.empty()) t=track.top(); } else break; } } } if(!track.empty()) cout<<"No."<<endl<<"FINISH"<<endl; else { cout<<"Yes."<<endl; j=0; for(i=0;i<n;i++) { cout<<"in"<<endl; track.push(a[i]); if(a[i]==target[j]) { cout<<"out"<<endl; j++; track.pop(); if(!track.empty()) t=track.top(); while(!track.empty()) { if(t==target[j]) { cout<<"out"<<endl; j++; track.pop(); if(!track.empty()) t=track.top(); } else break; } } } cout<<"FINISH"<<endl; } } return 0;}
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