PAT-B 1002. 写出这个数 (20) Stupid!

题目链接：点击打开题目链接

这个题需要注意的就是空格的输出，这应该属于这个题目的边界条件。

AC代码：

#include<iostream>#include<cstdio>using namespace std;int main(){char n;char num[10][5] = {"ling","yi","er","san","si","wu","liu","qi","ba","jiu"};int sum = 0,x;int g,s,b;while((n = getchar()) != '\n'){if(n =='0'){x = 0;}else if(n =='1'){x = 1;}else if(n =='2'){x = 2;}else if(n =='3'){x = 3;}else if(n =='4'){x = 4;}else if(n =='5'){x = 5;}else if(n =='6'){x = 6;}else if(n =='7'){x = 7;}else if(n =='8'){x = 8;}else if(n =='9'){x = 9;}sum += x;}if(!sum){cout << num[0] << endl;}else{b = sum/100;s = sum/10%10;g = sum%10;cout << !b?"":num[b];if(b != 0){cout << " ";}cout << (!s && !b)?"":num[s];if(b || !b&&s){cout << " ";}else if(s == 0 && b!=0){cout << "";}cout << num[g];}return 0;}

感觉自己好傻，sum+=n-'0'; 这一句话就可以代替所有的if-else。

这里是我第二次做到这个题目的做法，也是题目后面加上“Stupid!”的原因。