一个算法一个遗憾

来源：互联网发布：plc编程网站编辑：程序博客网时间：2024/04/28 07:35

好长时间都没写过算法类的程序,感觉比较不舒服.今天在网上看到了个题目,但实现之后还有Bug,很遗憾.

算法题目:需要将中文的数字字符串经过转换为数字也就是说一万二千三百四十五结果为 12345 是这样的

我的C#代码:

using System;using System.Collections.Generic;using System.ComponentModel;using System.Data;using System.Drawing;using System.Linq;using System.Text;using System.Windows.Forms;

namespace MyFirstWindowFormsProgram{ public partial class Form1 : Form { public Form1() { InitializeComponent(); }

private void button1_Click(object sender, EventArgs e) { string _bigNumber = textBox1.Text; string _smallNumber = ""; int j=0; long sum=0;

for (int i = 0; i < _bigNumber.Length; i++) { if (_bigNumber[i] == '亿') { long partSum = 0; long[] flag = new long[i - 1]; for (j = 0; j < i; j++) { switch (_bigNumber[j]) { case '一': flag[j] = 1; break; case '二': flag[j] = 2; break; case '三': flag[j] = 3; break; case '四': flag[j] = 4; break; case '五': flag[j] = 5; break; case '六': flag[j] = 6; break; case '七': flag[j] = 7; break; case '八': flag[j] = 8; break; case '九': flag[j] = 9; break; case '亿': flag[j] = 100000000; break; case '万': flag[j] = 10000; break; case '千': flag[j] = 1000; break; case '百': flag[j] = 100; break; case '十': flag[j] = 10; break; default: j++; break; } } for (int k = 0; k < j; k++) { if (flag[k] >= 10) { partSum += flag[k - 1] * flag[k]; } else if ((k == j - 1) && (flag[k] < 10)) { partSum += flag[k]; } } sum += partSum * 100000000; } else if (_bigNumber[i] == '万') { long partSum = 0; long[] flag = new long[i - j - 1]; for (int k = 0; k < i - j - 1; k++) { switch (_bigNumber[k]) { case '一': flag[k] = 1; break; case '二': flag[k] = 2; break; case '三': flag[k] = 3; break; case '四': flag[k] = 4; break; case '五': flag[k] = 5; break; case '六': flag[k] = 6; break; case '七': flag[k] = 7; break; case '八': flag[k] = 8; break; case '九': flag[k] = 9; break; case '千': flag[j] = 1000; break; case '百': flag[j] = 100; break; case '十': flag[j] = 10; break; default: j++; break; } } for (int k = 0; k < i - j - 1; k++) { if (flag[k] >= 10) { partSum += flag[k - 1] * flag[k]; } else if ((k == j - 1) && (flag[k] < 10)) { partSum += flag[k]; } } sum += partSum * 10000; } else { long partSum = 0; long[] flag = new long[i - j - 1]; for (int k = 0; k < i - j - 1; k++) { switch (_bigNumber[k]) { case '一': flag[k] = 1; break; case '二': flag[k] = 2; break; case '三': flag[k] = 3; break; case '四': flag[k] = 4; break; case '五': flag[k] = 5; break; case '六': flag[k] = 6; break; case '七': flag[k] = 7; break; case '八': flag[k] = 8; break; case '九': flag[k] = 9; break; case '千': flag[j] = 1000; break; case '百': flag[j] = 100; break; case '十': flag[j] = 10; break; default: j++; break; } } for (int k = 0; k < i - j - 1; k++) { if (flag[k] >= 10) { partSum += flag[k - 1] * flag[k]; } else if ((k == j - 1) && (flag[k] < 10)) { partSum += flag[k]; } } sum += partSum; } } textBox2.Text = sum.ToString(); } }}

遗憾的就是在运行的时候,编译器提示:

算术运算导致溢出。