c++map查找元素

map.count  统计个数，返回0或者1

map.find  返回迭代器

map<string,int> cmap;cmap["op1"] = 1;cmap["op2"] = 2;string str = "samy";cmap.insert(make_pair(str,3));//for(map<string,int>::iterator ite = cmap.begin(); ite!=cmap.end();++ite)//{//cout<<ite->first<<" "<<ite->second<<endl;//}//cout<<cmap.count("Annaa")<<endl;map<string,int>::iterator key = cmap.find("Anna");if(key!=cmap.end()){cout<<key->second<<endl;}