Bear and Three Balls
来源:互联网 发布:淘宝上买茶叶靠谱吗 编辑:程序博客网 时间:2024/04/29 11:16
Description
Limak is a little polar bear. He has n balls, the i-th ball has size ti.
Limak wants to give one ball to each of his three friends. Giving gifts isn't easy — there are two rules Limak must obey to make friends happy:
- No two friends can get balls of the same size.
- No two friends can get balls of sizes that differ by more than 2.
For example, Limak can choose balls with sizes 4, 5 and 3, or balls with sizes 90, 91 and 92. But he can't choose balls with sizes 5, 5and 6 (two friends would get balls of the same size), and he can't choose balls with sizes 30, 31 and 33 (because sizes 30 and 33 differ by more than 2).
Your task is to check whether Limak can choose three balls that satisfy conditions above.
Input
The first line of the input contains one integer n (3 ≤ n ≤ 50) — the number of balls Limak has.
The second line contains n integers t1, t2, ..., tn (1 ≤ ti ≤ 1000) where ti denotes the size of the i-th ball.
Output
Print "YES" (without quotes) if Limak can choose three balls of distinct sizes, such that any two of them differ by no more than 2. Otherwise, print "NO" (without quotes).
Sample Input
418 55 16 17
YES
640 41 43 44 44 44
NO
85 972 3 4 1 4 970 971
YES
Hint
In the first sample, there are 4 balls and Limak is able to choose three of them to satisfy the rules. He must must choose balls with sizes18, 16 and 17.
In the second sample, there is no way to give gifts to three friends without breaking the rules.
In the third sample, there is even more than one way to choose balls:
- Choose balls with sizes 3, 4 and 5.
- Choose balls with sizes 972, 970, 971.
#include<stdio.h>#include<string.h>int main(){int n,m;int num[1010];int flag=0;memset(num,0,sizeof(num));scanf("%d",&n);for(int i=0;i<n;i++){scanf("%d",&m);num[m]=1;}for(int i=0;i<1010;i++){if(num[i]==1&&num[i+1]==1&&num[i+2]==1){flag=1;break;}}if(flag)printf("YES\n");elseprintf("NO\n");}
- Bear and Three Balls
- Bear and Three Balls
- Bear and Three Balls
- Bear and Three Balls
- Bear and Three Balls
- Bear and Three Balls
- Bear and Three Balls
- Bear and Three Balls
- 【codeforces】Bear and Three Balls
- Bear and Three Balls CodeForces
- A. Bear and Three Balls
- acm Bear and Three Balls
- Codeforces 653A Bear and Three Balls
- codeforces->653A. Bear and Three Balls
- 【CodeForces】[653A]Bear and Three Balls
- CodeForces 653 A. Bear and Three Balls
- CodeForces 653A Bear and Three Balls
- 【Codeforces】-653A-Bear and Three Balls
- [游戏技术]求生之路服务器参数配置
- Java多线程系列--“JUC锁”02之 互斥锁ReentrantLock (r)
- 嘿,今天就是开始吧!
- linux软件安装管理与安装RPM时的挂载的概念
- 20160731------while循环、一维数组、Arrays类方法及练习
- Bear and Three Balls
- Go in Action - Manning 2016(读书笔记)
- 用javascript给type为hidden的input赋value值
- DAY22
- bzoj1014: [JSOI2008]火星人prefix
- ural 2071 - Juice Cocktails
- A. Brain's Photos
- linux线程私有数据详解
- 网络加载数据到ListView