字节序

什么是大小端？

例如：
90AB12CD
In big endian, you store the most significant byte in the smallest address. Here’s how it would look:

Address Value 1000 90 1001 AB 1002 12 1003 CD

In little endian, you store the least significant byte in the smallest address. Here’s how it would look:

Address Value 1000 CD 1001 12 1002 AB 1003 90

从Audio Recorder里读出来的byte array 数据是小端的, 可以用以下的代码转成Short

    public static short[] bytesToShorts(byte[] b) {        short[] s = new short[b.length / 2];        for (int i = 0; i < s.length; i++) {            s[i] = (short) ((b[i * 2] & 0xff) | ((b[i * 2 + 1] << 8) & 0xff00));        }        return s;    }

AudioRecord还可以直接读short

int read (short[] audioData, int offsetInShorts, int sizeInShorts)

write code to check the platform endian:

Suppose we are on a 32-bit machine.

If it is little endian, the x in the memory will be something like:

   higher memory      ----->+----+----+----+----+|0x01|0x00|0x00|0x00|+----+----+----+----+A|

&x

so (char*)(*x) == 1

If it is big endian, it will be:

+----+----+----+----+|0x00|0x00|0x00|0x01|+----+----+----+----+A|

&x

so this one will be ‘0’.