C++输出倒三角加数字

中兴笔试题目：

#include<iostream>using namespace std;class Triangle {public:explicit Triangle(int n) :rows(n), sum(0), count(0), temp(0) { maxNum = rows*(rows + 1); }void TriangleOutput();private:int rows;  //行数int maxNum;//表示三角中最大的数字int sum;  //自由变量int count;int temp;};void Triangle::TriangleOutput(){for (int r = 1;r <= rows;r++)//控制行{for (int a = 0;a < r - 1;a++)//先输出每行的”--“cout << "--";count = (4 * (rows - r) + 3);//用来缓存第r行的数字和“*”的总个数temp = (count + 1 )/ 2;for (int c = 1,left=sum+1, right = (maxNum - sum - rows + r)//每行右半三角的第一个值;c <=count; c++){if (c <= temp)//左半三角{if (c % 2 == 1){cout << left;left++;}if (c % 2 == 0)cout << "*";}if (c > temp) //右半三角{if (c % 2 == 1){cout << right;right++;}if (c % 2 == 0)cout << "*";}}sum = sum + rows - r + 1;//得到左半三角的左右边的值cout << endl;}cout << endl;}int main(){int n(0);cout << "请输入行数n:";cin >> n;Triangle Tr(n);Tr.TriangleOutput();return 0;}