数据解析(三):FastJson

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一.fastJson与Gson的用法基本一致

二.直接贴上代码了

//把java对象转换成json字符串    public void JavaToJson() {        Student stu = new Student("李毅", 23);        String s = JSON.toJSONString(stu);        System.out.println("javaToJSon:" + s);        //I/System.out: javaToJSon:{"name":"李毅","age":23}    }    //把list集合转换成json字符串    public void ListToJson() {        ArrayList<Student> data = new ArrayList<>();        for (int i = 0; i < 3; i++) {            Student stu = new Student("N" + i, i);            data.add(stu);        }        String s = JSON.toJSONString(data);        System.out.println("listToJSON:" + s);        //System.out: listToJSON:[{"name":"N0","age":0},{"name":"N1","age":1},{"name":"N2","age":2}]    }    //把json字符串转换成java对象    public void jsonToJava() {        Student student = new Student("李毅", 23);        String s = JSON.toJSONString(student);        JSON.parseObject(s,Student.class);        System.out.println("jsonToJava:" + student.toString());        //I/System.out: listToJSON:[{"name":"N0","age":0},{"name":"N1","age":1},{"name":"N2","age":2}]    }    //把json字符串转换成list集合对象    public void JsonToList() {        ArrayList<Student> data = new ArrayList<>();        for (int i = 0; i < 3; i++) {            Student stu = new Student("N" + i, i);            data.add(stu);        }        String json = JSON.toJSONString(data);      ArrayList<Student> coll = JSON.parseObject(json,new TypeReference<ArrayList<Student>>(){}.getType());        System.out.println("jsonToList:" + coll.size());        // I/System.out: jsonToList:3    }

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