function to count the number of "1" of one byte
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function to count the number of "1" of one byte ,for example 5(0101)has two "1"
经常遇到的面试题,毫无疑问需要借助位操作:
unsigned int bitCount (unsigned int value) { unsigned int count = 0; while (value > 0) { // until all bits are zero //if ((value & 1) == 1) // check lower bit // count++;count += value & 0x1; value >>= 1; // shift bits, removing lower bit//printf("value:%d, count:%d\n", value, count); } return count;}
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