浙大PAT甲级 1092

简单的字符串处理。

AC代码：

#include<iostream>#include<map>#include<cstdio>#include<algorithm>#include<queue>#include<cstring>#include<list>#include<set>#include<stack>#include<cmath>#include<vector>#define ll long long#define inf 999999999using namespace std;int main(){    string s;    string s1;    cin>>s>>s1;    int ans=0;    for(int i=0;i<s1.size();i++)    {        if(s.find(s1[i],0)==-1)        {            ans++;        }        else        {            int it=s.find(s1[i],0);            s.erase(it,1);        }    }    if(ans>0)    {        cout<<"No "<<ans;    }    else    {        cout<<"Yes "<<s.size()<<endl;    }}