java金额转换
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注：此程序是根据网上的一位网友的程序优化改编而来。因为该网友的网址记不清了，所以未注明原来的出处。见谅！
package com.work.util;/** * @author wangmj * 编写时间：2005-8-2 <br /> * 优化：2008-07-03 * 类的名称为：RMB.java <br /> * 比较完善的解决方案。 测试通过。 <br /> * 最准确的使用就是小数点之前最多13位，小数点之后不限,当然写多了也没有用，哈哈。<br /> */import java.text.DecimalFormat;import java.text.NumberFormat;//总体思路：//对数字进行分级处理，级长为4//对分级后的每级分别处理，处理后得到字符串相连//如：123456=12|3456//第二级：12=壹拾贰 + “万”//第一级：3456 =叁千肆百伍拾陆 + “”public final class RMB { private double amount = 0.0D; private static final String NUM = "零壹贰叁肆伍陆柒捌玖"; private static final String UNIT = "仟佰拾个"; private static final String GRADEUNIT = "仟万亿兆"; private static final String DOTUNIT = "角分厘"; private static final int GRADE = 4; private static final String SIGN = "￥"; private static final NumberFormat nf = new DecimalFormat("#0.###"); /** * 带参数的构造方法 * * @param amount */ private RMB(double amount) { this.amount = amount; } public static String toBigAmt(double amount) { nf.setMinimumFractionDigits(3);//小数点后不足的补零 String amt = nf.format(amount);//将double类型的数格式化并转换成字符串,实际上进行了四舍五入 System.out.println(amt); Double d = new Double(amount); String dotPart = ""; //取小数位 String intPart = ""; //取整数位 int dotPos; if ((dotPos = amt.indexOf('.')) != -1) { intPart = amt.substring(0, dotPos); dotPart = amt.substring(dotPos + 1); if(dotPart.length()>4){ //超过4位直接截取 dotPart = dotPart.substring(0,4); } } else { intPart = amt; } if (intPart.length() > 16) throw new java.lang.InternalError("数额太大，无法转换。"); String intBig = intToBig(intPart); String dotBig = dotToBig(dotPart); //以下代码稍做修改，现在好多了。 if ((dotBig.length() == 0) && (intBig.length() != 0)) { return intBig + "元整"; } else if ((dotBig.length() == 0) && (intBig.length() == 0)) { return intBig + "零元"; } else if ((dotBig.length() != 0) && (intBig.length() != 0)) { return intBig + "元" + dotBig; } else { return dotBig; } } /** * 用来处理几角几分几厘 * @param dotPart * @return */ private static String dotToBig(String dotPart) { //得到转换后的大写（小数部分） String strRet = ""; for (int i = 0; i < dotPart.length() && i < 3; i++) { int num; if ((num = Integer.parseInt(dotPart.substring(i, i + 1))) != 0) strRet += NUM.substring(num, num + 1) + DOTUNIT.substring(i, i + 1); } return strRet; } /** * 用来处理多少元 ，这个要仔细考虑才行 * @param intPart * @return */ private static String intToBig(String intPart) { //得到转换后的大写（整数部分） int grade; //级长 String result = ""; String strTmp = ""; //得到当级长 grade = intPart.length() / GRADE; //调整级次长度 if (intPart.length() % GRADE != 0) grade += 1; //对每级数字处理，先处理最高级，然后再处理低级的 for (int i = grade; i >= 1; i--) { strTmp = getNowGradeVal(intPart, i);//取得当前级次数字 result += getSubUnit(strTmp);//转换大写 //System.out.println(strTmp+"|"+getSubUnit(strTmp)); result = dropZero(result);//除零 去掉连续的零 //System.out.println("result="+result); //加级次单位 if (i > 1) //末位不加单位 //单位不能相连续 //注意：连续4个零的时候要特殊处理(wmj修改此bug) if(getSubUnit(strTmp).equals("零零零零")){ result = result+"零"; }else{ result += GRADEUNIT.substring(i - 1, i); } } return result; } private static String getNowGradeVal(String strVal, int grade) { //得到当前级次的串 String rst; if (strVal.length() <= grade * GRADE) rst = strVal.substring(0, strVal.length() - (grade - 1) * GRADE); else rst = strVal.substring(strVal.length() - grade * GRADE, strVal .length() - (grade - 1) * GRADE); return rst; } private static String getSubUnit(String strVal) { //数值转换 String rst = ""; for (int i = 0; i < strVal.length(); i++) { String s = strVal.substring(i, i + 1); int num = Integer.parseInt(s); if (num == 0) { //“零”作特殊处理 if (i != strVal.length()) //转换后数末位不能为零 rst += "零"; } else { //If IntKey = 1 And i = 2 Then //“壹拾”作特殊处理 //“壹拾”合理 //Else rst += NUM.substring(num, num + 1); //End If //追加单位 if (i != strVal.length() - 1)//个位不加单位 rst += UNIT.substring(i + 4 - strVal.length(), i + 4 - strVal.length() + 1); } } return rst; } /** * * @param strVal * @return */ private static String dropZero(String strVal) { //去除连继的“零” String strRst; String strBefore; //前一位置字符 String strNow; //现在位置字符 strBefore = strVal.substring(0, 1); strRst = strBefore; for (int i = 1; i < strVal.length(); i++) { strNow = strVal.substring(i, i + 1); if (strNow.equals("零") && strBefore.equals("零")) ;//同时为零 else strRst += strNow; strBefore = strNow; } //末位去零 if (strRst.substring(strRst.length() - 1, strRst.length()).equals("零")) strRst = strRst.substring(0, strRst.length() - 1); return strRst; } public static void main(String[] args) { System.out.println(RMB.toBigAmt(0.090D)); System.out.println(RMB.toBigAmt(10.090D)); System.out.println(RMB.toBigAmt(9.090D)); System.out.println(RMB.toBigAmt(9.290D)); System.out.println(RMB.toBigAmt(5.90D));// System.out.println(RMB.toBigAmt(10052345.00D));// System.out.println(RMB.toBigAmt(0.00D));// System.out.println(RMB.toBigAmt(0.60D));// System.out.println(RMB.toBigAmt(00.60D));// System.out.println(RMB.toBigAmt(150.2101D));// System.out.println(RMB.toBigAmt(15400089666.234D));// System.out.println(RMB.toBigAmt(15400089666.2347D));// System.out.println(RMB.toBigAmt(1111222233334444.2347D)); System.out.println(RMB.toBigAmt(111222233334444.2347D)); System.out.println(RMB.toBigAmt(11222233334444.2347D)); System.out.println(RMB.toBigAmt(1222233334444.2347D)); System.out.println(RMB.toBigAmt(222233334444.2347D));// System.out.println(RMB.toBigAmt(33334444.2347D));// java.math.BigDecimal bg = new java.math.BigDecimal(1111222233334444.2347D);// System.out.println(bg.toString());// //1111222233334444.25 BigDecimal也不是很准确 System.out.println(RMB.toBigAmt(22200004444.2347D));// //贰佰贰拾贰亿万肆仟肆佰肆拾肆元贰角叁分伍厘 System.out.println(RMB.toBigAmt(10004.2347D)); System.out.println(RMB.toBigAmt(22200000004.2347D)); System.out.println(RMB.toBigAmt(10400.0047D)); System.out.println(RMB.toBigAmt(1000000000000.23477777777777D)); System.out.println(RMB.toBigAmt(100100100.090566D)); //壹亿零壹拾万零壹佰元玖分 //壹亿零壹拾万零壹佰元玖分 }}
