flask 设置headers['Access-Control-Allow-Origin']='*'实现跨域访问

来源：互联网发布：公交车刷卡软件编辑：程序博客网时间：2024/05/21 12:43

需要flask将数据发送到web前端，定义一个路由，访问该路由获取数据。
res= make_response(json.dumps(result))：
通过make_response封装数据及类型转换，返回res即可。
一般纯的api接口需要考虑跨域访问问题，下面是简单的跨域访问装饰器在flask中的实现。

from functools import wrapsfrom flask import make_response一：@app.route('/result', methods=['GET', 'POST'])def index():    file_object = open('/home/pyspark_project/pyspark_output_result.json')    try:        result_text = file_object.read()    finally:        file_object.close()    #    rst = make_response(result_text)    rst.headers['Access-Control-Allow-Origin'] = '*'    # rst.headers['Access-Control-Allow-Methods'] = 'PUT,GET,POST,DELETE'    # allow_headers = "Referer,Accept,Origin,User-Agent"    # rst.headers['Access-Control-Allow-Headers'] = allow_headers    return rst, 201    #return result_text, 201 #, {'Content-Type': 'application/json'}二：@app.route('/articles_list/contents/')def json_contents():    response = make_response(jsonify(response=get_articles(ARTICLES_NAME)))    response.headers['Access-Control-Allow-Origin'] = '*'    response.headers['Access-Control-Allow-Methods'] = 'POST'    response.headers['Access-Control-Allow-Headers'] = 'x-requested-with,content-type'     return response

启动本地Flask Sever，准备响应 ajax

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