实现矩阵的转置&原矩阵与转置后矩阵的乘机

来源：互联网发布：稻谷出糙率计算数据编辑：程序博客网时间：2024/05/01 04:55
/** * Created by lihaibin02 on 2016/9/19. */public class Matrix_Operation {    //实现矩阵的转置    public static void reverse_Function() {        int a[][] = {{1, 2, 3, 4}, {1, 2, 3, 4}, {1, 2, 3, 4}, {1, 2, 3, 4}, {1, 2, 3, 4}, {1, 2, 3, 4}, {1, 2, 3, 4}};        int b[][] = new int[4][7];//b.length求行的长度，b[0].length求列的长度        for (int i = 0; i < 4; i++) {            for (int j = 0; j < 7; j++) {                b[i][j] = a[j][i];            }        }        result_Function(a, b);        System.out.println("矩阵a:");        for (int i = 0; i < 7; i++) {            for (int j = 0; j < 4; j++) {                if (j < 3) {                    System.out.print(a[i][j] + " ");                } else {                    System.out.println(a[i][j] + " ");                }            }        }        System.out.println("矩阵a转置:");        for (int i = 0; i < 4; i++) {            for (int j = 0; j < 7; j++) {                if (j < 6) {                    System.out.print(b[i][j] + " ");                } else {                    System.out.println(b[i][j] + " ");                }            }        }    }    //实现原矩阵与转置后的矩阵的乘机    public static void result_Function(int a[][], int b[][]) {        int c[][] = new int[7][7];        for (int r = 0; r < 7; r++) {            for (int h = 0; h < 7; h++) {                for (int k = 0; k < 4; k++) {                    c[r][h] += a[r][k] * b[k][h];                }            }        }        for (int i1 = 0; i1 < 7; i1++) {            for (int j1 = 0; j1 < 7; j1++) {                if (j1 < 6) {                    System.out.print(c[i1][j1] + " ");                } else {                    System.out.println(c[i1][j1] + " ");                }            }        }    }    public static void main(String[] args) {        reverse_Function();    }}-----------输出效果：矩阵a * 转置矩阵b：30 30 30 30 30 30 30 30 30 30 30 30 30 30 30 30 30 30 30 30 30 30 30 30 30 30 30 30 30 30 30 30 30 30 30 30 30 30 30 30 30 30 30 30 30 30 30 30 30 矩阵a:1 2 3 4 1 2 3 4 1 2 3 4 1 2 3 4 1 2 3 4 1 2 3 4 1 2 3 4 矩阵a转置:1 1 1 1 1 1 1 2 2 2 2 2 2 2 3 3 3 3 3 3 3 4 4 4 4 4 4 4 Process finished with exit code 0
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