LeetCode 136: Single Number
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Given an array of integers, every element appears twice except for one. Find that single one.
此题和389题如出一辙:
如果存在相同的数,异或一定会为0,剩下的就是那个单数
int singleNumber(int* nums, int numsSize) { int i, single = 0; for(i = 0; i < numsSize; ++i) single ^= nums[i]; return single;}
0 0
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