263. Ugly Number
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Write a program to check whether a given number is an ugly number.
在Discuss中看到的更简洁的Solution:
Ugly numbers are positive numbers whose prime factors only include 2, 3, 5
. For example, 6, 8
are ugly while 14
is not ugly since it includes another prime factor 7
.
Note that 1
is typically treated as an ugly number.
第一回写的solution,想得太多,代码冗杂,运行时间也偏长:
public class Solution { public boolean isUgly(int num) { if(num==1){ return true; } if(num==0){ return false; } while((num&1)==0){ num/=2; } if(num==1){ return true; } String sum_bit=Integer.toString(num); int sum=0; for(int i=0;i<sum_bit.length();++i){ sum=sum+sum_bit.charAt(i)-48; } while((sum%3)==0){ num/=3; sum_bit=Integer.toString(num); sum=0; for(int i=0;i<sum_bit.length();++i){ sum=sum+sum_bit.charAt(i)-48; } } if(num==1){ return true; } sum_bit=Integer.toString(num); char c=sum_bit.charAt(sum_bit.length()-1); while(c=='5'){ num/=5; sum_bit=Integer.toString(num); c=sum_bit.charAt(sum_bit.length()-1); } if(num==1){ return true; } else{ return false; } }}
再一回,想简单点:
public class Solution { public boolean isUgly(int num) { if(num==0) return false; while(num%2==0) num/=2; while(num%5==0) num/=5; while(num%3==0) num/=3; return num==1; }}
在Discuss中看到的更简洁的Solution:
public class Solution { public boolean isUgly(int num) { for(int i=2;i<6&&num>0;++i) while(num%i==0) num/=i; return num==1; }}
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