jsp Request获取url信息的各种方法

假设请求的页面是index.jsp,项目是WebDemo，则在index.jsp中获取有关request对象的各种路径信息如下 

String path = request.getContextPath(); 

String basePath = request.getScheme()+"://"+request.getServerName()+":"+request.getServerPort()+path+"/"; 

String remoteAddress=request.getRemoteAddr(); 

String servletPath=request.getServletPath(); 

String realPath=request.getRealPath("/"); 

String remoteUser=request.getRemoteUser(); 

String requestURI=request.getRequestURI(); 

out.println("path:"+path+"<br>"); 

out.println("basePath:"+basePath+"<br>"); 

out.println("remoteAddr:"+remoteAddress+"<br>"); 

out.println("servletPath:"+servletPath+"<br>"); 

out.println("realPath:"+realPath+"<br>"); 

out.println("remoteUser:"+remoteUser+"<br>"); 

out.println("requestURI:"+requestURI+"<br>"); 

结果： 

path:/WebDemo 

basePath:http://localhost:8683/WebDemo/ 

remoteAddr:127.0.0.1 

servletPath:/index.jsp 

realPath:D:\apache-tomcat-6.0.13\webapps\WebDemo\ 

remoteUser:null 

requestURI:/WebDemo/index.jsp 

 

从request获取各种路径总结： 

request.getRealPath("url");//虚拟目录映射为实际目录 

request.getRealPath("./");//网页所在的目录 

request.getRealPath("../");//网页所在目录的上一层目录 

假定你的web application(web应用)名称为news，你的浏览器中输入请求路径：http://localhost:8080/uploading/load.jsp 

request.getContextPath()  =>  /uploading 

request.getServletPath()  =>  /load.jsp 

request.getRequestURL()  =>  http://localhost:8080/uploading/load.jsp 

request.getRealPath("/")  =>   F:\learn\.metadata\.plugins\org.eclipse.wst.server.core\tmp0\wtpwebapps\uploading\ 

现在request.getRealPath("/") 这个方法已经不推荐使用了 

可以使用 

ServletContext.getRealPath(java.lang.String)  instead. 

request.getSession().getServletContext().getRealPath() 得到工程文件的实际物理路径,也就是绝对地址