leetcode 71. Simplify Path

Given an absolute path for a file (Unix-style), simplify it.

For example,
path = “/home/”, => “/home”
path = “/a/./b/../../c/”, => “/c”
click to show corner cases.

Corner Cases:
Did you consider the case where path = “/../”?
In this case, you should return “/”.
Another corner case is the path might contain multiple slashes ‘/’ together, such as “/home//foo/”.
In this case, you should ignore redundant slashes and return “/home/foo”.

public String simplifyPath(String path) {        Stack<String> result = new Stack<String>();        for(int i = 0;i < path.length();){            int j = i+1;            while(j < path.length() && path.charAt(j) != '/')                j++;            //System.out.println(path.substring(i,j));            if(path.substring(i,j).equals("/")) ;            else if(path.substring(i,j).equals("/.")) ;            else if(path.substring(i,j).equals("/..")){                if(!result.empty())                    result.pop();            }            else{                result.push(path.substring(i,j));            }            i = j;        }        if(result.empty())             return "/";        StringBuffer temp = new StringBuffer();        for(String str:result) temp.append(str);        return temp.toString();    }

教师里讨论问题真的很。。。。